Register to reply

Triangles and Definite Integrals

by apt403
Tags: definite, integrals, triangles
Share this thread:
Jul4-12, 01:47 AM
P: 46
I'm trying to figure out how to integrate a data set, without knowing the function. While doing this, I got to thinking about this:

If the definite integral of a function can be represented by the area under that function, bound by the x axis, then shouldn't:

[itex]\int_{a}^{b}2x\frac{\mathrm{d} }{\mathrm{d} x} = A = 1/2b*h[/itex]

Where the integral is bound by a = 0 and b = 2, and the triangle's base is 2 and height is 2.

but rather,

[itex]\int_{0}^{2}2x\frac{\mathrm{d} }{\mathrm{d} x} = 4[/itex]


[itex]A = 2[/itex]

Where's the discrepancy?
Phys.Org News Partner Science news on
Security CTO to detail Android Fake ID flaw at Black Hat
Huge waves measured for first time in Arctic Ocean
Mysterious molecules in space
Jul4-12, 02:04 AM
P: 88
The triangle's height is not 2.
Jul4-12, 02:06 AM
P: 46
Brain fart. I'm an idiot.

Register to reply

Related Discussions
Definite Integrals of Definite Integrals Calculus & Beyond Homework 7
Definite Integrals Precalculus Mathematics Homework 7
Definite Integrals Calculus & Beyond Homework 11
Definite Integrals... Calculus 6
Definite integrals Introductory Physics Homework 9