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A thin 1.0-m rod pivoted at one end falls (rotates) frictionlessly from a vertical position, starting from rest. What is the angular speed of the rod when it is horizontal? [Hint: Consider the center of mass and use the conservation of mechanical energy.]
So far I'm thinking that intial potential energy = final kinetic energy, so
mgh = K, where h = 0.5 m (the center of mass)
I can't seem to use K = 1/2 * Icm * w2 + 1/2 * M * vcm2
because I don't know vcm... or can I find it?
So far I'm thinking that intial potential energy = final kinetic energy, so
mgh = K, where h = 0.5 m (the center of mass)
I can't seem to use K = 1/2 * Icm * w2 + 1/2 * M * vcm2
because I don't know vcm... or can I find it?