- #1
mrdoe
- 36
- 0
Find
[tex]\displaystyle\int\dfrac{\sec ^2\sqrt{x}}{\sqrt{x}} dx[/tex]
We're supposed to use u du substitution but I can't seem to get this one.
EDIT: Sorry I didn't read rules.
I tried [tex]u=\sec^2\sqrt{x}[/tex] and all variants. Usually it was in the form of
[sec or cos][^2 or none][sqrt x]
[tex]\displaystyle\int\dfrac{\sec ^2\sqrt{x}}{\sqrt{x}} dx[/tex]
We're supposed to use u du substitution but I can't seem to get this one.
EDIT: Sorry I didn't read rules.
I tried [tex]u=\sec^2\sqrt{x}[/tex] and all variants. Usually it was in the form of
[sec or cos][^2 or none][sqrt x]