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Homework Statement
A block with a mass of 4 kg slides from rest a distance of 2 m down a frictionless inclined plane where it encounters a spring. It compresses the spring a distance 1.4 m before stopping. The inclined plane makes an angle q = 35° with the horizontal. What is the value of the spring constant?
Homework Equations
F=-kx
F=MA
The Attempt at a Solution
First, the force on the block = Mass (4) times acceleration. (9.81)
The force of the block when it touches the spring is 39.24.
So, the force the spring exerts is equal and opposite.
39.24 = -kx
X=1.4, so it should be easy:
39.24 = -k 1.4
-k = 28.028
k = -28.028
But this is not right...