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livewire5
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http://img94.imageshack.us/img94/4392/ppcapqs2.png
http://img267.imageshack.us/img267/5059/ppcapqs1.png
In this question the charge is calculated by isolating Q in E=surface charge density/absalon not
My question is, the electric field of an infinite charged plane is E=surface charge density/(2*absalon naught)because the electric field in center of parallel plate capacitor are parallel we add
surface charge density/(2*absalon naught)+surface charge density/(2*absalon naught)
to give us E between the electrodes to be surface charge density/absalon notbut when that question uses that formula to find the charge, shouldn't the charge found be divided by 2 to get the charge on each electrode since that formula we initially created by adding the E of both electrodes n this question asks to find charge on each electrode...so what i am really saying is that why isn't the Q in that formula (in that link) charge of both electrodes (their magnitude ofcourse) why is that Q the charge on one electrode?
http://img267.imageshack.us/img267/5059/ppcapqs1.png
In this question the charge is calculated by isolating Q in E=surface charge density/absalon not
My question is, the electric field of an infinite charged plane is E=surface charge density/(2*absalon naught)because the electric field in center of parallel plate capacitor are parallel we add
surface charge density/(2*absalon naught)+surface charge density/(2*absalon naught)
to give us E between the electrodes to be surface charge density/absalon notbut when that question uses that formula to find the charge, shouldn't the charge found be divided by 2 to get the charge on each electrode since that formula we initially created by adding the E of both electrodes n this question asks to find charge on each electrode...so what i am really saying is that why isn't the Q in that formula (in that link) charge of both electrodes (their magnitude ofcourse) why is that Q the charge on one electrode?
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