- #1
_Stew_
- 7
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Given a function: z(x,y) = 2x +2y^2
Determine ∂x/∂y [the partial differentiation of x with respect to y],
Method 1:
x = (z/2) - y^2
∂x/∂y = -2y
Method 2:
∂z/∂x = 2
∂z/∂y = 4y
∂x/∂y = ∂x/∂z X ∂z/∂y = (1/2) X 4y = 2y
One or both of these is wrong. Can someone point out where I went wrong? I started to wonder why this was happening as I was looking over some fluid mechanics problems (above problem is unrelated to my original problem but if I understand the above problem it will help)
Thanks
Determine ∂x/∂y [the partial differentiation of x with respect to y],
Method 1:
x = (z/2) - y^2
∂x/∂y = -2y
Method 2:
∂z/∂x = 2
∂z/∂y = 4y
∂x/∂y = ∂x/∂z X ∂z/∂y = (1/2) X 4y = 2y
One or both of these is wrong. Can someone point out where I went wrong? I started to wonder why this was happening as I was looking over some fluid mechanics problems (above problem is unrelated to my original problem but if I understand the above problem it will help)
Thanks