- #1
goaliemon89
- 2
- 0
Here is what the question asks:
Find the coordinate of all points in the graph of y=3e^x - x^3 at which the tangent line passes through the point (1,0).
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I am told that the 2 points are (-.872, -1.027) and (2.275, 13.657). Any help at all that you can give will be very much appreciated.
I was thinking of letting the 2 coordinates be (X1, Y1) and (X2, Y2), calculating the slope of the line through (1,0) and one of these points, and setting this slope equal to the derivative of y=3e^x - x^3 ...but I seem to be going no where.
Suggestions?
Find the coordinate of all points in the graph of y=3e^x - x^3 at which the tangent line passes through the point (1,0).
----------------------------
I am told that the 2 points are (-.872, -1.027) and (2.275, 13.657). Any help at all that you can give will be very much appreciated.
I was thinking of letting the 2 coordinates be (X1, Y1) and (X2, Y2), calculating the slope of the line through (1,0) and one of these points, and setting this slope equal to the derivative of y=3e^x - x^3 ...but I seem to be going no where.
Suggestions?