How Is the Effective Stiffness of an Interatomic Bond Calculated in Iron?

[magma_saber]

Homework Statement

One mole of iron has a mass of 56 grams and density of 7.87 g/cm^3. You have a long thin bar of iron, 2.0 m long, with a square cross section, 0.12 cm on a side. You hang the rod vertically and attach a 151 kg mass to the bottom, and you observe that the bar becomes 1.03 cm longer. Calculate the effective stiffness of the interatomic bond, modeled as a "spring":

Homework Equations

Y= (F/A)/(dL/L
Y=ks/d

The Attempt at a Solution

Y=[(151*9.8)/(0.12e-2)²]/[(1.03e-2)/2]

 

[magma_saber]

nvm i solved it

 

[tomcue]

= 1.5 x 10^12 N/m^2

The effective stiffness of the interatomic bond in this scenario is calculated to be 1.5 x 10^12 N/m^2. This value represents the strength of the bond between iron atoms in the rod, modeled as a spring. It is important to note that this is only an approximation and the actual stiffness may vary depending on factors such as temperature and impurities in the material. However, this calculation gives us a general idea of the interatomic stiffness of iron in this specific situation. Further research and experimentation would be needed to determine the true interatomic stiffness of iron in different conditions.