Bound Vector and Vector Products

In summary, bound vectors are vectors that are localized in space and require a specific point of application to be fully specified. They are different from free vectors, which only require a magnitude and direction. Bound vectors can be added, subtracted, and used in dot and cross products with free vectors, but when adding two bound vectors with different points of application, their combined action must be calculated on something. This also applies to finding the dot and cross product of two bound vectors with different initial points. However, vectors directed along two skew lines can still form a vector cross product, yielding a vector parallel to the line that is perpendicular to both original skew lines.
  • #1
Ali Asadullah
99
0
I have read in a book about bound vectors that we can not move them i mean that they can not move parallel to any location. Can someone please give me an example. Also if we are given two bound vectors, is it possible to find the dot and cross product of two vectors.
 
Mathematics news on Phys.org
  • #2
Ali Asadullah said:
Can someone please give me an example.

Hi Ali! :smile:

A typical bound vector is a force vector …

the line of application of the force is an essential part of the force, since two equal forces along different parallel lines will have a different effect (when applied to a body which is allowed to rotate).

(Actually, I notice that http://en.wikipedia.org/wiki/Free_vector" [Broken] uses a different definition of bound vector … it requires the initial point of a bound vector to be fixed in space, while so far as I know, in physics, it is only necessary for the line of a bound vector to be fixed in space.)
Also if we are given two bound vectors, is it possible to find the dot and cross product of two vectors.

Dot product and cross product of bound vectors work in exactly the same way as for free vectors (in the cross product case, one assumes that all the bound vectors have the same initial point). :smile:
 
Last edited by a moderator:
  • #3
Sir i am asking about a vector which can not be moved from its position i.e what is given on Wikipedia. Sir i think you have told me about a sliding vector which can be moved any where on its line of action. Thanks
 
  • #4
Hello Ali,

You have posted this in the physics, not maths sections so I will try to give you a physics answer.

Before we can have any vectors we must have a coordinate system and an origin.

You have probably been told that vectors are 'something with magnitude and direction'.
This is true of all types of vectors, but some types require further information.

Vectors that are not localised in space are called free vectors. This type only requires a magnitude and direction to fully specify them. Velocity is a good example of a free vector. A translation is another. A mechanical couple is a third.

Some vector types are localised in space. These are called localised or bound vectors. These vectors start or finish at a particular point in our coordinate system. To fully specify a bound vector we need to specify this point as well as a magnitude and direction. (We only need specify one point the other is given by the magnitude and direction.) Good examples of bound vectors are the displacement vector, the position vector and the moment of a force.

My three examples for free and bound vectors roughly correspond.
Notice I have not mentioned the Force vector. This is because it can take on either guise depending upon the application - you have to recognise which is involved.

As regards to calculations, you can freely mix n match localised and non localised vectors, adding, subtracting, forming dot and cross products. This is because the free vector will always include the point of application of the bound vector in its domain.

To illustrate consider the ship in the sketches.

Fig 1
Shows a ship drifting freely in the tide. It picks up the velocity of the tide, whcih is a free vector.

Fig2
The ship is now under power and has a heading velocity. This is also a free vector, as is the resultant velocity shown by the vector triangle.

Fig3
Shows what happens as the ship drops anchor at A. It no longer possesses any velocity, but it is subject to a force from the tide. This force has a moment about the anchor point and cause the ship to swing round to Fig 4.

Fig4
The ship is now at equilibrium in between the bound force of the tension in the anchor chain and the tidal force as before.

and yes, Wiki is correct.
 

Attachments

  • ships.jpg
    ships.jpg
    13.7 KB · Views: 1,569
  • #5
Thank you Studiot, one last question can we find the product of two bound vectors which don't have same initial point. What i think that for cross-product, vectors should have same initial point.(If we have free vectors, we can get same initial point by sliding a vector to a position parallel to itself) but now we have bound vectors which we can not move or slide. So we can not find the cross product of two bound vectors with different initial points. Am i right sir and this was the case of cross product, can we find the dot product of two bound vectors with different initial points.
 
  • #6
Vectors directed along two skew lines can still form a vector cross product. Don't forget we have to work in 3D for this stuff.

This product yields the vector parallel to the line which is perpendicular to both the original skew lines.

I don't know if you have done any vector geometry, this is more advanced.

The vector equation of a line through a point a [tex]({a_1},{a_2},{a_3})[/tex] in a specific direction, ie parallel to a specific vector b [tex]({b_1},{b_2},{b_3})[/tex] is

r = a +tb where r is the position vector and t is a parameter (scalar)

or

(x,y,z) = [tex]({a_1},{a_2},{a_3})[/tex] + t[tex]({b_1},{b_2},{b_3})[/tex]



Let the two lines be

r = a +tb and r = a'+sb'

The vector perpendicular to both lines is

[tex]n\quad = \quad b \otimes b'[/tex]
 
  • #7
i recently watched these posts, but may i ask can we find the sum of two bound vectors which don't have same initial point. can we just treat them like free vectors, and move them freely parallel to find the sum of vector (to determine the direction and magnitude), while keeping the real position(ie, initial point of the resultant vector) unknown?
 
  • #8
Hello hoshii and welcome,

Hijacking someone else's thread with your own question is not good etiquette. You also get better results starting your own thread.

However your question does progress this thread so here is an answer.

You can only add (calculate the combined action of) bound vectors with different points of application by their action on something. When you do this you will not only obtain the vector sum by sliding one to form a triangle as you described, you will also find their vector product produces an effect.

For example consider two bound forces acting at different points on a body (rigid or deformable) . The body will translate according to the vector resultant of these forces. It will also rotate according to the resultant moment from these same forces.
 
  • #9
Thanks for your advice and help.
 

1. What is a bound vector?

A bound vector, also known as a fixed vector, is a vector that has both magnitude and direction and is fixed to a specific point or origin.

2. How is a bound vector represented?

A bound vector is typically represented by an arrow pointing from the origin to the endpoint, with the length of the arrow representing the magnitude and the direction of the arrow representing the direction of the vector.

3. What is the difference between a bound vector and a free vector?

A free vector, also known as a sliding vector, is a vector that is not fixed to a specific point or origin and can be moved parallel to itself without changing its magnitude or direction. A bound vector, on the other hand, is fixed to a specific point and cannot be moved without changing its magnitude and direction.

4. What is a vector product?

A vector product, also known as a cross product, is a mathematical operation that combines two vectors to produce a new vector that is perpendicular to both input vectors. It is denoted by the symbol "×" and is used to find the area of a parallelogram formed by the two input vectors.

5. How is the magnitude of a vector product calculated?

The magnitude of a vector product is calculated by taking the product of the magnitudes of the two input vectors and the sine of the angle between them. It can also be calculated by taking the product of the area of the parallelogram formed by the input vectors and the sine of the angle between them.

Similar threads

Replies
7
Views
1K
  • General Math
Replies
11
Views
1K
Replies
2
Views
127
Replies
14
Views
988
Replies
8
Views
1K
  • General Math
Replies
2
Views
1K
  • General Math
Replies
4
Views
3K
Replies
9
Views
1K
Replies
2
Views
773
Back
Top