Formula to Calculate Bending Moment of Beam Under UDL and Point Load

In summary: UDL) applied at the same point?What is the formula for bending moment of a vertical beam subjected to a point load and a UDL on the top of it (load applied axially)?That would be a centrally loaded column, if I understand correctly.
  • #1
buytree
34
1

Homework Statement


1.What is the formula to calculate the bending moment of a beam subjected to UDL?
2.What is the formula to calculate the bending moment of a beam subjected to point load?

Homework Equations



Bending moment (UDL) = WL^2/8 (Kg-mm or Kg-m)

Bending moment (point load) = Force x Distance ( This is actually for a horizontal beam with load acting is a point load) (Kg-mm or Kg-m)

What is the formula for bending moment of a vertical beam subjected to a point load and a UDL on the top of it (load applied axially)?

The Attempt at a Solution



I come through several formulas, like (W * X)(X/2) when a UDL is acting over the cantilever beam. I am bit confused how do they arrive with these formulas and where should I use what?
 
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  • #2


buytree said:

Homework Statement


1.What is the formula to calculate the bending moment of a beam subjected to UDL?
2.What is the formula to calculate the bending moment of a beam subjected to point load?

Homework Equations



Bending moment (UDL) = WL^2/8 (Kg-mm or Kg-m)

Bending moment (point load) = Force x Distance ( This is actually for a horizontal beam with load acting is a point load) (Kg-mm or Kg-m)

What is the formula for bending moment of a vertical beam subjected to a point load and a UDL on the top of it (load applied axially)?

The Attempt at a Solution



I come through several formulas, like (W * X)(X/2) when a UDL is acting over the cantilever beam. I am bit confused how do they arrive with these formulas and where should I use what?

Well a UDL is like a "rectangularly" distributed load, so the load effectively acts at the center of the beam i.e. at a distance of L/2. Since the entire length is L, the load is WL (since UDL = W N/m)

so BM = Force*distance = (WL)(L/2)
 
  • #3


You also need to know something about how the ends of the beam are supported. Are they fixed, free, or simply supported?
 
  • #4


For a horizontal simply supported beam of length L subject to udl w, the maximum bending moment is at the centre and equal to
wL^2/8 distributed along the span parabolically.
For a horizontal simply supported beam of length L, and subject to a point load P at mid-span, the maximum bending moment is PL/4. If the point load is applied at aL (0<a<L) from one end, the maximum bending moment is Pa(1-a)/L just under the load.
The bending moment at any other point on the span can be found by simple statics.

"What is the formula for bending moment of a vertical beam subjected to a point load and a UDL on the top of it (load applied axially)?"
That would be a centrally loaded column, if I understand correctly.
 
  • #5


SteamKing: The ends are fixed, there is no movement in any direction.
 
  • #6


Thanks everyone for your effects in helping me.
rock.freak667 said:
Well a UDL is like a "rectangularly" distributed load, so the load effectively acts at the center of the beam i.e. at a distance of L/2. Since the entire length is L, the load is WL (since UDL = W N/m)

so BM = Force*distance = (WL)(L/2)

mathmate said:
For a horizontal simply supported beam of length L subject to udl w, the maximum bending moment is at the centre and equal to
wL^2/8 distributed along the span parabolically.
Check the above post by rock.freak667, it says BM = (WL)(L/2) and you say wL^2/8. I am guessing wL^2/8 is the right BM for the beam, then what's the other formula for?
For a horizontal simply supported beam of length L, and subject to a point load P at mid-span, the maximum bending moment is PL/4. If the point load is applied at aL (0<a<L) from one end, the maximum bending moment is Pa(1-a)/L just under the load.
The bending moment at any other point on the span can be found by simple statics.

"What is the formula for bending moment of a vertical beam subjected to a point load and a UDL on the top of it (load applied axially)?"
That would be a centrally loaded column, if I understand correctly.
Yes exactly it is a centrally loaded column which is subjected to load on top of it, so what's the BM for UDL and point load?
 
  • #7


rock.freak667 will have to interpret the application of his formula.
wL^2/8 is the maximum BM at the centre of a udl of w kg/m for a simply supported beam.

In fact, all these questions about formulas can be resolved by standard tables available in books or the web, such as:
http://structsource.com/analysis/types/beam.htm [Broken]

You will find the required formulas for the fixed supports subject to udl in your case at the above link. Bending moments at different lengths along the span has to be obtained by superimposing the simply supported moment (parabolic) with the end moments by statics.

For the vertical "beam", are both loads (point and udl) applied vertically and axially?

A centrally loaded column not subject to lateral loads does not incur first order bending moments. Second and higher order bending moments could be caused by lateral buckling or deflections (P-delta effects).
 
Last edited by a moderator:
  • #8


mathmate:In the above link you gave if I use the formula for the FIXED-FIXED BEAM WITH UNIFORM LOAD (my case), my BM at the center would be for x=L/2 is WL^2/24. Hoping this would help, let me check and get back to you. Thanks mathmate.

And my column is only loaded vertically downward over the top. Sorry I might have confused in the above posts.
 
  • #9


Maximum positive bending moment at the centre of wL^2/24 is correct for a fixed-fixed beam.

If you are doing the design of a beam, do not forget that the negative support moments of wL^2/12 are higher than that at the centre.

Draw the bending moment diagram would make it clear.
 
  • #10


mathmate said:
Maximum positive bending moment at the centre of wL^2/24 is correct for a fixed-fixed beam.

If you are doing the design of a beam, do not forget that the negative support moments of wL^2/12 are higher than that at the centre.

Draw the bending moment diagram would make it clear.

I assume the above case is only for the horizontal beams, what about the BM for column with UDL and point load?
 
  • #11


As per my previous response:

"A centrally loaded column not subject to lateral loads does not incur first order bending moments. Second and higher order bending moments could be caused by lateral buckling or deflections (P-delta effects)."

Is the column monolithic with other structures? If so, there would have to be bending moments at the junctions and would not be considered as purely centrally loaded.

This bending moment (at the junction of beam/column) has to be calculated with an indeterminate structural analysis taking into account of the loads on the beam, size (stiffness) of the beams and columns, and load on the column, the possible deflections due to lateral (wind, earthquake, etc.) or asymmetrical loading, etc.
 
  • #12


Thanks. I got it.
 

1. What is the formula for calculating the bending moment of a beam under a UDL and point load?

The formula for calculating the bending moment of a beam under a UDL and point load is M = (wL^2)/8 + P*a, where M is the bending moment, w is the UDL (uniformly distributed load), L is the length of the beam, P is the point load, and a is the distance from the point load to the nearest support.

2. How do I determine the direction of the bending moment in a beam under a UDL and point load?

The direction of the bending moment in a beam under a UDL and point load can be determined by using the right-hand rule. Point your right thumb in the direction of the load and curl your fingers. The direction of the bending moment will be perpendicular to your curled fingers.

3. What is the unit of measurement for the bending moment in the formula?

The unit of measurement for the bending moment in the formula is Newton-meters (Nm) or pound-feet (lb-ft).

4. Can the formula be used for any type of beam?

Yes, the formula can be used for any type of beam as long as the beam is subject to a UDL and point load. However, it is important to note that the material properties and cross-sectional shape of the beam will also affect the bending moment.

5. How accurate is the formula for calculating the bending moment of a beam under a UDL and point load?

The formula is an approximation and may not be 100% accurate due to various factors such as the assumption of a perfectly straight beam and neglecting any additional loads or moments. However, it is a commonly used formula in engineering and provides a good estimate for most practical applications.

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