De Broglie wavelength and Fermi wavelength

In summary: The De Broglie wavelength is nothing but the de Broglie wavelength of electrons near the Fermi energy. Most of the properties of solids, involving electronic transport, are described by the dynamics of the electrons near the Fermi energy. While describing the transport of these particular electrons, one has to account for their scattering by a potential. This potential could be a result of disorder or lattice vibrations (phonons). If the variations in this potential are comparable to the de Broglie (or Fermi) wavelength then quantum effects become more prominent. If, however, this is not the case, i.e. the potential is slowly varying, then one can use the semi-classical description of the
  • #1
zhdx
12
0
As we know that the properties of nanoscale material are quite diffrent from the bulk's. But what's the threshold of the size, or what the upper limmit where significant difference can be observed? The De Broglie wavelength or the Fermi wavelength of the electron in material? How to understand that?
 
Physics news on Phys.org
  • #2
The threshold where one approximation takes over from another one is fractal in nature - it depends on the situation being studied and what you want to know about it.
 
  • #3
zhdx said:
As we know that the properties of nanoscale material are quite diffrent from the bulk's. But what's the threshold of the size, or what the upper limmit where significant difference can be observed? The De Broglie wavelength or the Fermi wavelength of the electron in material? How to understand that?

The Fermi wavelength is nothing but the de Broglie wavelength of electrons near the Fermi energy. Most of the properties of solids, involving electronic transport, are described by the dynamics of the electrons near the Fermi energy. While describing the transport of these particular electrons, one has to account for their scattering by a potential. This potential could be a result of disorder or lattice vibrations (phonons). If the variations in this potential are comparable to the de Broglie (or Fermi) wavelength then quantum effects become more prominent. If, however, this is not the case, i.e. the potential is slowly varying, then one can use the semi-classical description of the system; one example is the Boltzmann transport equation. In this regime, we have used "semi" because we still use band theory, which is quantum, but ignore the wave nature of the electrons in these bands.

Another example where one encounters a rapidly varying potential is in a semiconductors quantum well. Here is one example:

http://www.intenseco.com/images/graphics/technology/figure-1-quantum_well_intermixing.png

The width of the quantum well typically ranges from a couple of nanometers to a couple of tens of nanometers. There is, however, one major difference between this well and the 1D quantum well one encounters in standard quantum mechanics. Say that the above figure represents the potential profile along the z direction; the potential in the xy plane, however, is flat. For electrons whose energies lie inside the well, there are a macroscopic number of states which can travel in the xy plane, while still being confined in the z direction. In a way, you could consider this structure as "bulk" in the xy plane and "nanoscale" in the z direction. This distinction comes from the fact that there are macroscopic numbers of "modes" in the xy plane, while there are only a few modes in the z direction. By "modes" I simply mean traveling states. The modes in the z direction are analogous to the discrete eigenstates of the 1D quantum well like:

http://britneyspears.ac/physics/fbarr/images/qwdiag.gif

As you increase the width of the well more modes will start getting squeezed into the well. When the well is sufficiently wide you will have a macroscopic number of modes. Consequently, you now have a macroscopic number of modes in all three directions, which is what happens in a bulk solid. Now, instead of only having a potential well in the z direction you could have decided to have it in two directions. In that case you will end up with the quantum wire. Alternatively, if you choose to have a potential well in all three directions, then you would end up with a quantum dot. You can read more about this here:

www.phys.ttu.edu/~cmyles/Phys5335/Lectures/12-2-10.ppt

OR

http://users.ece.gatech.edu/~alan/E...tures/King_Notes_Density_of_States_2D1D0D.pdf
 
Last edited by a moderator:

1. What is the De Broglie wavelength?

The De Broglie wavelength is a concept in quantum mechanics that describes the wavelength associated with a particle. It is named after French physicist Louis de Broglie, who proposed that all particles, including matter, have a wave-like nature, and the wavelength of this wave is inversely proportional to the particle's momentum.

2. How is the De Broglie wavelength calculated?

The De Broglie wavelength (λ) can be calculated using the following formula: λ = h / p, where h is the Planck's constant (6.626 x 10^-34 J*s) and p is the momentum of the particle. This formula is applicable to all particles, including electrons, protons, and even macroscopic objects, such as baseballs.

3. What is the significance of the De Broglie wavelength?

The De Broglie wavelength is significant because it helps to understand the wave-particle duality of matter. It shows that particles can exhibit both wave-like and particle-like behavior. This concept is crucial in understanding the behavior of particles at the subatomic level and has applications in various fields, including quantum mechanics, chemistry, and electronics.

4. What is the Fermi wavelength?

The Fermi wavelength, also known as the de Broglie wavelength of a fermion, is the wavelength associated with a fermionic particle at its Fermi energy. It is named after Italian physicist Enrico Fermi and is defined as λ = h / √(2mE), where m is the mass of the particle and E is its Fermi energy. It is a fundamental concept in condensed matter physics and is used to describe the spatial distribution of electrons in a solid material.

5. How does the Fermi wavelength differ from the De Broglie wavelength?

The Fermi wavelength and De Broglie wavelength differ in their applications and the type of particles they describe. The De Broglie wavelength is applicable to all particles, while the Fermi wavelength is specifically used for fermions, such as electrons. Additionally, the Fermi wavelength takes into account the particles' energy and mass, while the De Broglie wavelength is solely dependent on the particle's momentum.

Similar threads

  • Special and General Relativity
Replies
27
Views
1K
  • Quantum Interpretations and Foundations
Replies
2
Views
1K
  • Other Physics Topics
Replies
5
Views
855
  • Quantum Interpretations and Foundations
Replies
6
Views
2K
  • Quantum Interpretations and Foundations
Replies
3
Views
849
  • Quantum Interpretations and Foundations
Replies
1
Views
1K
  • High Energy, Nuclear, Particle Physics
Replies
6
Views
2K
  • High Energy, Nuclear, Particle Physics
Replies
6
Views
1K
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
14
Views
2K
Back
Top