- #1
ProBasket
- 140
- 0
A cup of coffee at 174 degrees is poured into a mug and left in a room at 76 degrees. After 5 minutes, the coffee is 134 degrees. Assume that the differential equation describing Newton's Law of Cooling is (in this case) dT/dt = k(T-76)
here's what i done:
[tex]y(0) = 98e^{kt}[/tex]
y(5) = 134-76 = 58, so...
98e^{5k} = 58
k = -0.104904
[tex]y(15) = 98*e^{15*-0.104904} + 76[/tex]
and got 159.8448 which is wrong. anyone know where i went wrong?
here's what i done:
[tex]y(0) = 98e^{kt}[/tex]
y(5) = 134-76 = 58, so...
98e^{5k} = 58
k = -0.104904
[tex]y(15) = 98*e^{15*-0.104904} + 76[/tex]
and got 159.8448 which is wrong. anyone know where i went wrong?