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Finding the general expression of the nth term |
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| Jul6-12, 08:54 AM | #1 |
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Finding the general expression of the nth term
1. The problem statement, all variables and given/known data
Given successive terms of numbers starting from the 1st term: 11, 21, 35, 53, 75, 101,... What is the general expression of the nth term? where n is positive integer 2. Relevant equations / 3. The attempt at a solution Can't find a good attempt. |
| Jul6-12, 09:02 AM | #2 |
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Could this be an arithmetic or geometric sequence??
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| Jul6-12, 09:05 AM | #3 |
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Recognitions:
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| Jul6-12, 09:15 AM | #4 |
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Finding the general expression of the nth term
sorry I don't know...
how will you determine a general expression for it in this problem without trial and error? is it like finding a needle in the ocean? |
| Jul6-12, 10:07 AM | #5 |
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look at the terms, then form a sequences of differences and what do you get?
10 , 14, 18, 22, 26 ... look at the differences as a sequence and what do you see? write an expression to generate the differences sequence term(n)= term(0) + 4*(n-1) where n=1, 2, 3, 4... then write an expression to generate your sequence using the differences expression TERM(n) = TERM(0) + ... |
| Jul6-12, 10:32 AM | #6 |
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Ouw... I think you can use the Sn to calculate the Un...
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