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Solve the complex analysis problem 
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#1
Feb2712, 03:49 AM

P: 43

The problem is attached
regards, chwala ken 


#2
Feb2712, 08:48 AM

P: 179

Nope dude, that's incorrect. x and y are wrong. Try forming a realvalued denominator and then check again what x and y are.



#3
Mar1012, 02:15 AM

P: 43

i do not get it ? A complex number has a Real part and an Imaginary part. The idea is to breakdown the expression in the form x+iy so i do not understand why you are talking of real valued denominator. Kindly expound by looking at the problem and check where i went wrong.



#4
Mar1012, 04:39 AM

P: 179

Solve the complex analysis problem
Suppose z=1/(a+i*b)
Then z not equal to 1/a + i*1/b Why? Basic fraction calculus. You cannot "split up" a fraction among its denominator, which is what you're intending. You can split it up among the nominator though, so you should make the denominator realvalued by expanding with its complex conjugate, that is z=(ai*b)/((a+i*b)*(ai*b))=(ai*b)/(a^2+b^2) so your final expression would be a/(a^2+b^2)i*b/(a^2+b^2) If you don't understand the above, my advice would be to real a bit about basics of complex numbers on wikipedia (no offense) 


#5
Mar1212, 03:48 AM

P: 43

Ha..,Thanks Susskind for the insight.



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