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Calculating Emitter Current - Voltage-Divider Bias

by ?n0t_A_nUmb3R?
Tags: bias, current, emitter, voltagedivider
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?n0t_A_nUmb3R?
#1
Jun20-14, 02:34 PM
P: 12
I am aware that there are two methods of working out IE for a Voltage-Divider circuit.

The first is:
https://www.google.co.za/search?q=VB...l%3B2048%3B730
And then work out VE = VB - VBE

And the second is:
https://www.google.co.za/search?q=vt...ml%3B480%3B257
(VTH and RTH)

I then tried to calculate a specific problem using both methods. The results were not consistent and varied.
My question is can we use both methods (first and second above) interchangeably?
Are there any differences between the two methods?
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mfb
#2
Jun20-14, 03:26 PM
Mentor
P: 11,869
Quote Quote by ?n0t_A_nUmb3R? View Post
I then tried to calculate a specific problem using both methods. The results were not consistent and varied.
Then please show what you did and which setup you mean. Otherwise it is hard to tell what went wrong.
?n0t_A_nUmb3R?
#3
Jun23-14, 04:34 PM
P: 12
There is a difference of 0.31mA. Is this still acceptable?
Can I also use these methods interchangeably? (Voltage Divider Method and VTH/RTH Method)

mfb
#4
Jun23-14, 05:11 PM
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P: 11,869
Calculating Emitter Current - Voltage-Divider Bias

I don't understand your equation for IE. A difference of 6% is a bit large for rounding errors.
?n0t_A_nUmb3R?
#5
Jun23-14, 06:16 PM
P: 12
As I know it to be, it is basically simplifying the circuit using Thevenins Theorem.
Problem is I don't know where to use it.
From the examples I've worked it seems as if I can use this method OR the voltage divider method.
But in some instances, there is a considerate difference in my calculations.
My lecturer is out of office at the moment. So unfortunately I cannot email him.
Attached Files
File Type: pdf Thevenins Equivalent.pdf (349.4 KB, 4 views)
?n0t_A_nUmb3R?
#6
Jun23-14, 06:21 PM
P: 12
I do realize that the Thevenins method is for loading effects and the voltage-divider method is for unloaded effects. But I have come across questions where they do not mention whether the circuit is loaded or not.
NascentOxygen
#7
Jun23-14, 11:35 PM
HW Helper
Thanks
P: 5,311
You must inevitably arrive at the same answer, unless you make different or wrong approximations along the way, or through oversight or blunder.


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