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BMWPower06
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Homework Statement
A catapult on a cliff launches a large round rock towards a ship on the ocean below. The rock leaves the catapult from a height H of 32.0 m above sea level, directed at an angle q above the horizontal with an unknown speed v0.
http://img230.imageshack.us/img230/5669/cliffvl5.gif [Broken]
The projectile remains in flight for 6.00 seconds and travels a horizontal distance D of 158.0 m. Assuming that air friction can be neglected, calculate the value of the angle q.
Calculate the speed at which the rock is launched.
Homework Equations
X = Xo+ Vot+.5at^2
V=Vo+at
V^2= Vo^2 + 2a (X-Xo)
The Attempt at a Solution
So i drew a FBD and got:
Xo= 0
X= 158 m
Yo= 32m
Y= 0
a= -9.8 m/s^2
i tried to use the X=Xo... equation but I am not sure what to do with theta. In other words, what does theta equal in this equation? i know its going to be Xsin/cos theta, but don't know what to do.
Thanks
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