- #1
Pengwuino
Gold Member
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Homework Statement
I'm looking to do the surface integral of [tex]\oint {\vec v \cdot d\mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}}
\over a} } [/tex] where v is arbitrary and in spherical coordinates and the surface is the triangle enclosed by the points (0,0,0) -> (0,1,0) -> (0,1,1) -> (0,0,0).
The Attempt at a Solution
Now the obvious method is to convert the differential area to cartesian giving [tex]\int_0^y {\int_0^1 {\vec v \cdot dydz} } \hat x[/tex]. However, I want to know how this would be done in spherical. The limits are what confuse me, would they be something like [tex]
\int_{\pi /2}^{\pi /4} {\int_0^{r\sin \theta } { - v \cdot r\sin \theta drd\theta } } \hat \theta[/tex]? That can't make sense because obviously the integral is all screwed up then... Come to think of it, that area element doesn't even make sense...
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