How to Prove that A*B= |A||B|cos theta

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In summary, the problem asks to prove that A*B = |A||B|cos theta and the solution utilizes the Law of Cosines and the properties of dot product to show that a*b = abcostheta.
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ARJewell
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Homework Statement


Prove that A*B = |A||B|cos theta


Homework Equations


Law of cosines: c^2= a^2 + b^2 - 2abcostheta
Property of a dot product; x*x=x^2
Replace c^2, a^2, and b^2 with dot product

The Attempt at a Solution



c*c=a*a+b*b-2abcostheta
since c=a-b
c*c= (a-b) * (a-b)
c*c= (a*a-2a*b+b*b)

therefore
(a*a-2a*b+b*b) = a*a+b*b-2abcostheta
-2a*b=-2abcostheta
a*b=abcostheta


Does this look right?
 
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  • #2
It looks right to me. If you need to refer to all the rules you apply in each step of your proof, you should probably notice that you utilized that the inner product is commutative and distributive.
 

1. How do I know which values to use for A and B in the equation A*B= |A||B|cos theta?

To use this equation, you will need to know the magnitude (length) and direction (angle) of both vectors A and B. This will allow you to calculate the dot product of the vectors, which is equal to A*B*cos theta. The magnitude of a vector can be found using the Pythagorean theorem and the direction can be found using trigonometric functions.

2. What is the significance of the cosine function in this equation?

The cosine function in this equation represents the angle between vectors A and B. It is used to find the dot product of the two vectors, which is necessary in order to prove that A*B= |A||B|cos theta.

3. Can this equation be used for any two vectors, regardless of their dimensions?

Yes, this equation can be used for any two vectors in two or three-dimensional space. However, it cannot be used for vectors in higher dimensions.

4. How does this equation prove that A*B= |A||B|cos theta?

This equation is derived from the definition of the dot product of two vectors. By finding the dot product of vectors A and B, and comparing it to the right side of the equation, which represents the product of their magnitudes and the cosine of the angle between them, we can see that they are equal. This proves that A*B= |A||B|cos theta.

5. Are there any real-life applications of this equation?

Yes, this equation has many real-life applications in fields such as physics, engineering, and mathematics. It is commonly used to calculate work done by a force, torque, or power in physics, and in finding the angle between two vectors in engineering and navigation. It is also used in mathematical proofs and calculations involving vectors.

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