- #1
Romperstomper
An electron is accelerated through a potential difference of 240V, what is it's speed?
I used energy conservation to find it.
So, here's what I did:
[tex] 0 = \frac{1}{2} m\Delta v^2 + q\Delta V[/tex]
[tex]240V*(1.6*10^-19C) = \frac{1}{2} * (9.1*10^-31kg )* V^2[/tex]
[tex]V = 9.2*10^6 m/s[/tex]
Is this correct, or am I doing something wrong?
I used energy conservation to find it.
So, here's what I did:
[tex] 0 = \frac{1}{2} m\Delta v^2 + q\Delta V[/tex]
[tex]240V*(1.6*10^-19C) = \frac{1}{2} * (9.1*10^-31kg )* V^2[/tex]
[tex]V = 9.2*10^6 m/s[/tex]
Is this correct, or am I doing something wrong?