## I saw this awhile ago, and always meant to ask about it but kept forgetting.

Anyways I always thought this story was cute, but I was wondering how you would solve the math problem? http://sports.yahoo.com/blogs/nfl-sh...5977--nfl.html I thought it would be 20% for all four games and then .16 percent for each game, but I guess that's wrong. Some people are saying you would do a 1 minus the probability which I don't understand at all, so anyone who wants to take the time to explain it to me I'd appreciate it. Oh thanks in advance, and also this isn't a homework problem, well it is but it's not my homework problem.

 Recognitions: Homework Help (my answer was wrong.)
 Recognitions: Homework Help The Bears win one game with probability .2 so they win 4 games with probability .2^4=.2*.2*.2*.2=.0016 When no that the Packers win all four games is the opposite of the Bears win at least one game, the probability of the opposite is q=1-p. The Bears win at least one game with probability 1-.8^4