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TheClockmaker
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Homework Statement
A train on the planet surface of Mars is traveling along a banked track shaped as large circle with a radius of 500m.
Q. Assuming Mars gravity is 3.8m/s[itex]^{2}[/itex] what Velocity v must the Martian train travel to simulate a total artificial gravity equal to Earth's 9.81m/s[itex]^{2}[/itex]?
Q. And what is the correct angle [itex]\theta[/itex] for this to be a frictionless banked turn?
Homework Equations
v=Velocity
[itex]\theta[/itex]=Angle of track bank
r=Radius of track
g=Mars Gravity of 3.8m/s[itex]^{2}[/itex]
e=desired artificial gravity of 9.81m/s[itex]^{2}[/itex]
v=[itex]\sqrt{rg \tan \theta}[/itex]
[itex]\theta[/itex]=arctan [itex]\frac{v^{2}}{rg}[/itex]
The Attempt at a Solution
I'm not in school, I'm just doing this for fun out of curiosity, but I've been working on this for over a week now and I am stuck.
Using Excel I'm able to calculate the bank angle with my formula: =DEGREES(ATAN(v^2/(r*g)))
The best that have come up with is to calculate v so that it will equal my desired Earth gravity of 9.81 so I came up with this: =SQRT(r*9.81)
I derived at that using a=[itex]\frac{v^{2}}{r}[/itex] and substituting 9.81 for a.
So this calculates to: v=70.0357051795725 and [itex]\theta[/itex] angle of 68.8256331451085 degrees.
But my formula 9.81=[itex]\frac{v^{2}}{r}[/itex] does not factor in the gravity existing on Mars at all and I don't know how to do this; i assume that i need to be sutbracting the downward acceleration of 3.8 in relationship to the cosine of the angle; but then I won't know the angle until I know the aceleration, so I am just stuck. Any help is appreciated, I've spent so long on this problem I can't put it down now, it's driving me crazy. If you would, please help me to know what I need to do to my formulas. Thanks.
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