Limit of ln as x goes to infinity

In summary, the problem is to find the limit of (lnx)^2/x as x approaches infinity. The solution involves using L'Hopital's Rule. The original attempt at a solution provided does not make sense and the correct approach is to take the limit of (lnx)^2 as x approaches infinity, which is equal to infinity.
  • #1
Cacophony
41
0

Homework Statement


lim (lnx)^2/x
x-->infinity


Homework Equations



none

The Attempt at a Solution



=5lnx/x * (1/lnx)/(1/lnx)

=5/(x/lnx)

How do I calculate x/lnx?
 
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  • #2
Cacophony said:

The Attempt at a Solution



=5lnx/x * (1/lnx)/(1/lnx)

=5/(x/lnx)

How do I calculate x/lnx?

I do not follow you. What have you done?

ehild
 
  • #3
Cacophony said:

Homework Statement


lim (lnx)^2/x
x-->infinity


Homework Equations



none

The Attempt at a Solution



=5lnx/x * (1/lnx)/(1/lnx)
Where did the 5 come from? In fact, where did any of this come from? What you have makes zero sense to me.

Also, since you haven't taken the limit yet, you should not get rid of the "lim" symbol.
Cacophony said:
=5/(x/lnx)

How do I calculate x/lnx?

This is a problem that is suited to L'Hopital's Rule. Have you covered it yet?
 
  • #4
Cacophony said:

Homework Statement


lim (lnx)^2/x
x-->infinity

Cacophony,

what you typed is equivalent to:

[tex]\displaystyle \lim_{x\to \infty}\dfrac{[ln(x)]^2}{x}[/tex]



Did you intend

[tex]\displaystyle \lim_{x\to \infty}[ln(x)]^{\frac{2}{x}} \ ?[/tex]
 

1. What is the limit of ln as x goes to infinity?

The limit of ln as x goes to infinity is infinity. This means that as x approaches infinity, the value of ln(x) also approaches infinity.

2. How do you calculate the limit of ln as x goes to infinity?

To calculate the limit of ln as x goes to infinity, you can use the L'Hopital's Rule or the properties of limits. For example, if the limit is in the form of ln(x)/x, you can rewrite it as 1/x and then take the limit as x approaches infinity.

3. Why does ln increase without bound as x goes to infinity?

The natural logarithm function, ln(x), is an increasing function, which means that as x increases, the value of ln(x) also increases. As x approaches infinity, the value of ln(x) will continue to increase without bound, meaning it has no finite limit.

4. Can the limit of ln as x goes to infinity be negative?

No, the limit of ln as x goes to infinity cannot be negative. Since the natural logarithm function is always positive for positive values of x, the limit as x approaches infinity will also be positive or infinity.

5. Is there a graph that can help visualize the limit of ln as x goes to infinity?

Yes, the graph of ln(x) can help visualize the limit of ln as x goes to infinity. As x approaches infinity, the graph of ln(x) will continue to increase without bound in the positive direction.

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