Is This Solution to the Integral and Series Problem Correct?

In summary, the integral of 3x^2e^x dx is equal to 3x^2e^x-6xe^x+6e^x+C. This was obtained using integration by parts twice. Additionally, the question was asked for a divergent series with terms that go to 0, and it was confirmed that the harmonic series 1/n meets this criteria. Finally, the suggestion was made to differentiate the expression (3x^2-6x+6)e^x+C to verify the solution.
  • #1
bengaltiger14
138
0

Homework Statement


Evaluate the integral 3x^2e^xdx



The Attempt at a Solution



I used integration by parts twice and came up with:

3x^2e^x-6xe^x+6e^x+C

Does that look correct.


Another question ask for a divergent series whose terms go to 0.
The harmonic series 1/n (with infinity on top of summation and n=1 on bottom) fits that criteria correct?
 
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  • #2
1. google the integrator and check
2. yes you are correct
 
  • #3
Even more simply, differentiate (3x2- 6x+ 6)ex+ C and see what you get!
 
  • #4
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