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wmrunner24
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Homework Statement
Because of Earth’s rotation about its axis, a point on the Equator experiences a centripetal acceleration of 0.034 m/s2, while a point at the poles experiences no centripetal acceleration.
What is the apparent weight at the equator of a person having a mass of 118.1 kg? The
acceleration of gravity is 9.8 m/s^2 .
Answer in units of N.
Homework Equations
F[tex]_{centripetal}[/tex]=ma[tex]_{centripetal}[/tex]
F[tex]_{gravity}[/tex]=mg
The Attempt at a Solution
So, at first this problem greatly confused me. Now I think I have an idea of how to approach it.
F[tex]_{centripetal}[/tex]=F[tex]_{gravity}[/tex]-F[tex]_{normal}[/tex]
This equation describes the net force toward the center of the Earth. Gravity acts toward the center of the Earth, while the normal force will resist it. If a person were to be standing on a scale, it would be the normal force that would produce the "apparent" reading. So then:
F[tex]_{normal}[/tex]=F[tex]_{gravity}[/tex]-F[tex]_{centripetal}[/tex]
F[tex]_{normal}[/tex]=mg-ma[tex]_{centripetal}[/tex]
F[tex]_{normal}[/tex]=1153.3646 N
Is this line of thinking correct? Thanks in advance for any help provided.