## train gets struck by lightning

Yeah, I guess you'd define the earth-frame as non-moving.

 Quote by I like Serena So can you answer the question how much time passes between the first and second strike if an observer behind the train observes them at the same time?
i think so...taking into account the height of the train "h" and the distance between the observer and the train to be "x", i would say the time it takes for the closer lightning strike to reach the observer behind the train would be t1=[sq.rt(x^2+h^2)]/c. the time t2, for the further lightning strike to reach the observer would be ("L" being the length of the train), t2=[sq.rt((x+L)^2+h^2)]/c, so the difference in time for the ground observer behind the train would be Δt=t2-t1.

if we ignore the height of the train and assume all this happens at say eye level, t1=x/c and t2=(x+L)/c, and Δt=t2-t1

 Quote by I like Serena In retrospect I'm starting to wonder. You are so persistent in putting both observers in the same place. And you are so eager to apply the Lorentz transformation. It suggests that you are supposed to use it and to make that assumption.
i honestly am not sure really, the way i am doing the problem now is simply classical mechanics, and considering we are doing special relativity in class it seems strange that i wouldnt have to apply things i am learning in class. i acknowledge that this question seems a little vague. im going to ask my prof. tomorrow to get a better idea. i appreciate your help, thanks.

 Tags special relativity