Triple Integral and volume

In summary, the question asks for the volume of a domain bounded by a paraboloid and a cone, and the answer is (5*Pi)/6, using cylindrical coordinates. The individual asking for confirmation has correctly solved the problem.
  • #1
Juggler123
83
0
Just needing to check an answer really. The question is as follows;

The domain bounded by the surface of a paraboloid z=2-x^2-y^2 and that of a cone z^2=x^2+y^2 is given by D = ( x,y,z : x^2+y^2 [tex]\leq[/tex] 1, sqrt(x^2+y^2) [tex]\leq[/tex] z [tex]\leq[/tex] 2-x^2-y^2 ). Find its volume using the appropriate coordinate system.

I've used cylindrical coordinates for this problem and found the answer to be (5*Pi)/6. Can anyone tell me if this is actually correct or have a made a mistake somewhere along the way?

Thanks!
 
Physics news on Phys.org
  • #2
Juggler123 said:
Just needing to check an answer really. The question is as follows;

The domain bounded by the surface of a paraboloid z=2-x^2-y^2 and that of a cone z^2=x^2+y^2 is given by D = ( x,y,z : x^2+y^2 [tex]\leq[/tex] 1, sqrt(x^2+y^2) [tex]\leq[/tex] z [tex]\leq[/tex] 2-x^2-y^2 ). Find its volume using the appropriate coordinate system.

I've used cylindrical coordinates for this problem and found the answer to be (5*Pi)/6. Can anyone tell me if this is actually correct or have a made a mistake somewhere along the way?

Thanks!

That's exactly correct.
 

1. What is a triple integral?

A triple integral is a mathematical concept used to find the volume of a three-dimensional object. It involves integrating a function over a three-dimensional region, often represented as a rectangular prism in Cartesian coordinates.

2. How is a triple integral different from a regular integral?

A regular integral finds the area under a curve in a two-dimensional space, while a triple integral finds the volume under a surface in a three-dimensional space. This means that a triple integral involves integrating over three variables, as opposed to two variables in a regular integral.

3. What is the formula for a triple integral in Cartesian coordinates?

The formula for a triple integral in Cartesian coordinates is ∭ f(x,y,z) dV, where f(x,y,z) is the function being integrated and dV represents the infinitesimal volume element.

4. How is the order of integration determined in a triple integral?

The order of integration is determined by the type of region being integrated over. In general, it is easiest to start with the most "outer" variable and work towards the most "inner" variable. This can also be determined by drawing a graph of the region and visualizing which variable is changing the most rapidly.

5. What are some applications of triple integrals?

Triple integrals have many real-world applications, such as calculating the mass and center of mass of a three-dimensional object, finding the volume of a solid with varying density, and determining the probability of a particle being in a certain region in quantum mechanics. They are also used in engineering, physics, and computer graphics.

Similar threads

Replies
5
Views
1K
Replies
2
Views
1K
Replies
3
Views
1K
Replies
3
Views
2K
Replies
3
Views
637
  • Calculus
Replies
9
Views
2K
Replies
4
Views
341
Replies
3
Views
2K
  • Calculus
Replies
2
Views
1K
Back
Top