Velocity of Water in 5 cm Tube: Solve Equation

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In summary, water is being forced through a tube with a radius of 5 cm and connected to a tube with a radius of 1 cm at a rate of 10 liters/min. The pressure in the 5 cm tube is 1×10^5 Pa and the density of water is 1000 kg/m3. Using the equation for flow rate of liquid, it can be determined that the velocity of the water in the 5 cm tube is not directly given and requires unit conversions. Converting liters to milliliters and minutes to seconds may help in finding the correct equation.
  • #1
coldsteel
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1.A tube of radius 5 cm is connected to tube of radius 1 cm. Water is forced through the tube at a rate of 10 liters/min. The pressure in the 5 cm tube is 1×10^5 Pa. The density of water is 1000 kg/m3. Assume that the water is nonviscous and uncompressible.
What is the velocity of the water in the 5 cm radius tube?


2. Flow rate of liquid = Velocity X Area.
3. I believe the units are messing me up. I am not sure about the 10 liters/min. but my equation: 10 liters/min = (1000)x(5^2)(∏)(V) I am not coming up with the correct answers, and don't know if this is even close to the right equation. can somone point me in the right direction?
 
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  • #2
The volume and area need to have the same length units.
 
  • #3
convert the Liters into milliliters (L-mL) and use the conversion 1mL=1cm^3 than change minutes into seconds (1min=60sec)
 

What is the equation for calculating the velocity of water in a 5 cm tube?

The equation for calculating the velocity of water in a 5 cm tube is v = Q/A, where v is the velocity, Q is the volumetric flow rate, and A is the cross-sectional area of the tube.

How do I solve the equation for velocity of water in a 5 cm tube?

To solve the equation for velocity of water in a 5 cm tube, you will need to know the volumetric flow rate and the cross-sectional area of the tube. You can then plug these values into the equation v = Q/A and solve for v.

What units should I use for the equation to calculate the velocity of water in a 5 cm tube?

The units for velocity should be in meters per second (m/s), the units for volumetric flow rate should be in cubic meters per second (m^3/s), and the units for cross-sectional area should be in square meters (m^2).

Can I use this equation for tubes with different diameters?

No, this equation is specifically for tubes with a diameter of 5 cm. If you want to calculate the velocity of water in a tube with a different diameter, you will need to use a different equation that takes into account the specific dimensions of the tube.

What factors can affect the velocity of water in a 5 cm tube?

The velocity of water in a 5 cm tube can be affected by factors such as the pressure of the water, the viscosity of the water, and any obstructions or bends in the tube that may cause turbulence.

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