How many photons does it emit?

[GravityGirl]

a 1-kW raido transmitter operates at 880kHz. How many photons per second does it emit?

Power=work/time
Power=change in KE/time

f=1/T
T=1/880kHz

so 1 kw=change in KE/1.136x10^-6

change in KE=.00136 J

i don't know if i am doing this right. please point me in the right direction.

 

[Kurdt]

You know the frequency (880kHz) of the photons and thus you can work out their energy with an equation you haven't written down. Then you know how much energy it uses per second (1 kW) and you can find the amount of photons per second from that?

 

[m2003]

To calculate the number of photons being emitted by the 1-kW radio transmitter, we need to use the formula relating energy of a photon (E) to its frequency (f): E = hf, where h is Planck's constant (6.626x10^-34 J*s).

First, we need to convert the frequency from kHz to Hz: 880 kHz = 880,000 Hz.

Next, we can calculate the energy of each photon at this frequency: E = (6.626x10^-34 J*s)(880,000 Hz) = 5.82x10^-28 J.

Then, we can use the power of the transmitter (1 kW = 1000 J/s) to calculate the number of photons emitted per second: 1000 J/s / 5.82x10^-28 J = 1.72x10^31 photons/s.

Therefore, the 1-kW radio transmitter at 880 kHz is emitting approximately 1.72x10^31 photons per second.