Nuclear Fission: Understanding the Role of Heavy Nuclei and Lighter Options

In summary, the binding energy prevents fissioning of lighter nuclei. Lighter nuclei that are used for fission are U-233, Th-232, and B-10. Technically, when B-10 absorbs a neutron, it fissions into L-7 and He-4, but that doesn't yield much energy/unit mass.
  • #1
spideyinspace
41
0
i have some basic doubts...why is that nuclear fission is done only on heavy nucleus..what stops to perform nuclear fission on lighter nucleus..what are the lighter nucleus that are used for fission if any?
 
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  • #2
Binding energy basically prevents fissioning of lighter nuclei.

The lightest nucleus readily fissioned by low energy neutrons is U-233. Th-232 can be fission by fast neutrons.

Technically, when B-10 absorbs a neutron, it fissions into L-7 and He-4, but that doesn't yield much energy/unit mass.

One can obtain spallation reactions, but that doesn't really mean fission.
 
  • #3
Yes, fission of nucleus lighter than Fe, no energy is gained. And fusion above Fe you don't gain energy.

http://www.alaskajohn.com/physics/charts/binding_energy.jpg

You see that the peak is around Fe-56; most energy / nucleon in average.

The idea of nuclear-power is to use this binding energy to get a net gain of energy =)
 
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  • #4
how the temperature and energy release is calculated in fission and fussion...i mean,any general formula for the calculation of temperature and energy released in fission/fussion for any element...
 
  • #5
what has temperature with anything to do?

on what level do you want the answer?

The first level is that you compare the total (mass and kinetic) energy of the nuclies before and after reaction. The total mass will be smaller or larger after the reaction (if you fissile a nucleus heavier than iron). The "lost" mass is then transformed into kinetic energy of the reaction products.
 
  • #6
malawi_glenn said:
Yes, fission of nucleus lighter than Fe, no energy is gained. And fusion above Fe you don't gain energy.

http://www.alaskajohn.com/physics/charts/binding_energy.jpg

You see that the peak is around Fe-56; most energy / nucleon in average.

The idea of nuclear-power is to use this binding energy to get a net gain of energy =)

cant you not gain energy? you just transfer it or something

and don't you need about 300 million degrees to have fissio/fussion (forgot which one is where you combine two molecules) be a viable source without wasting energy put into it.
 
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  • #7
malawi_glenn said:
what has temperature with anything to do?

on what level do you want the answer?

The first level is that you compare the total (mass and kinetic) energy of the nuclies before and after reaction. The total mass will be smaller or larger after the reaction (if you fissile a nucleus heavier than iron). The "lost" mass is then transformed into kinetic energy of the reaction products.

i mean the heat released...

so are u saying that only the energy released can be found...what are the different energies released, is it only heat ...is there anyway so that we can find the energy released which is in the form of heat...
 
  • #8
the neutrons released in the fission bombards other nuclear fuel also,so it would be a chain reaction...would the neutrons released in fission bombard the fission products and would it continue bombarding the fission products again and again..is this possible...Or neutrons bombard only the nuclear fuel and not the nuclear fission products...
 
  • #9
ben328i said:
cant you not gain energy? you just transfer it or something

and don't you need about 300 million degrees to have fissio/fussion (forgot which one is where you combine two molecules) be a viable source without wasting energy put into it.

No this is more complex that this, but still very elementary. When you fuse two protons, you gain 2.22 MeV which is the binding energy of the deutron. Look at this picture:
http://www.alaskajohn.com/physics/charts/binding_energy.jpg
When you go towards iron from H, you bind the nucleus harder and harder, so when you fuse togheter nucleis up to Iron, energy is gained. You get more energy than you put in. But if you fuse two nucleis heavier than iron, the system is more loosley bound, and you get less energy than you put in.

Standard thing you should know in introductory nuclear physics.
 
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  • #10
spideyinspace said:
i mean the heat released...

so are u saying that only the energy released can be found...what are the different energies released, is it only heat ...is there anyway so that we can find the energy released which is in the form of heat...

Dont know how that is done in theory, only empiracally. Well approx 80% of the energy is carried away by the fissile products, the rest is shared by the neutrons, gamma etc

I would recommend K.S Kranes "Introductory nuclear phyics" book, chapter 13.
 
  • #11
malawi_glenn said:
No this is more complex that this, but still very elementary. When you fuse two protons, you gain 2.22 MeV which is the binding energy of the deutron. Look at this picture:
http://www.alaskajohn.com/physics/charts/binding_energy.jpg
When you go towards iron from H, you bind the nucleus harder and harder, so when you fuse togheter nucleis up to Iron, energy is gained. You get more energy than you put in. But if you fuse two nucleis heavier than iron, the system is more loosley bound, and you get less energy than you put in.

Standard thing you should know in introductory nuclear physics.

ya i have no clue what that link is trying to say. i kinda get that h4 is like the most productive.

ya i have only taken an intro to physics. need more math to move up.
but wasn't someone trying to do (fission/fusion forgot which one is which) with lasers and either (break apart or bond again forgot which goes where) the nuclei together kinda forgot still interesting though.
 
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  • #12
There is not so much math needed to understand this on this level. I can ensure you that (almost) every intro book on modern physics cover this.
 
  • #13
nice.
ya that's my problem right now.
need to start physics but can't until calc
cant do calc till done with trig
cant do trig until done with allg
so ya...
a few years from now and i will be helping you :P
 
  • #14
are the fission products random...is there any way we can predict the fission products and the energy released..any general formuala or relation for fission...
what would be the temperature of nuclear fission reactors...
 
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  • #15
yes the fission products are random, they follow a distribution. Se for example:

http://www.science.uwaterloo.ca/~cchieh/cact/nucfig/fissionyield.gif

So therefore, the expression for how much energy that is relased is (semi)emperically measured.

In a fission reactor using water as moderator. the water is boiling. The rods with the Uran is approx 800K, if i remember correct, was three years science I had nuclear reactor science on the schedule =)
 
  • #16
malawi_glenn said:
yes the fission products are random, they follow a distribution. Se for example:

http://www.science.uwaterloo.ca/~cchieh/cact/nucfig/fissionyield.gif

So therefore, the expression for how much energy that is relased is (semi)emperically measured.

In a fission reactor using water as moderator. the water is boiling. The rods with the Uran is approx 800K, if i remember correct, was three years science I had nuclear reactor science on the schedule =)

the temperature u mentioned is low i think...cant the fission reactions produce million kelvin temperature..is it so,only fusion can produce million kelvin of temperature...
 
  • #17
.. you have made a misstake now.

Millions of kelvin is NEEDED to have a fusion reactor.

Think once more, can you contain medium of 1million kelvin? No, you need strong magnetic fields. Do you use magnetic-cages in fission reactors? No.

The point is I don't remember if it is 1200K or 800K...
 
  • #18
stars have million kelvin temperature because of fusion..if fusion can produce this much temperature then why can't the fission produce million kelvin temperature...am confussed..
 
  • #19
Fission and fusion if two totaly sperate things.

Fission you split a nucleu and due to the relased binding energy parts fly away and heat the rod (heat is motion/vibration, when nucleis are split, the fragments are beeing breaked in the rod, and that makes heat) and the rod will heat the water. As a water boiler, you have a metal rod, which gets warm, like 500K, and that makes the water boil.

The stars are hot in its interior due to huge gas compression due to gravitational collapse. And in order to overcome the coloumb barrier (two similar charges repel each other), lots of energy/velocity of the protons is needed. So in order do have many partilces(protons) undergo fusion is to have high heat (heat is average velocity/kinetic energy of particles). So in stars, the temperature from grav-collapse (the gas law tells you that if you compress gas, temp will rise) can make the hydrogen ions (protons) undergo fusion, which releases energy (photons) that can halt the gas from beeing gravitationally collapsed into a degenerate remnant or black hole. The sun is 15millions kelivn in the center and 6000K on the "surface".

But on earth, we can't have a big thing like the sun on earth, and if you have 15million K in a container... things melt... (melt at approx 6000K so we can't even reach 15million K in an ordinary container). So one uses strong magnetic fields, you know that charges in motion in magnetic fields are bent. So you contain this hot hot plasma in magnetiv cages on earth.

I don't have time to give you a more lengthy answer than this, I suggest you wait for more people to reply or either (better) consult textbooks from your library in introductory nuclear physics and stellar physics.
 
  • #20
is it possible atleast theoritically to bombard a lighter nuclues than uranium and having Atomic number >60 if we use a very high energy neutron...so that there won't be any need for uranium in future if this is possible...
 
  • #21
spideyinspace said:
is it possible atleast theoritically to bombard a lighter nuclues than uranium and having Atomic number >60 if we use a very high energy neutron...so that there won't be any need for uranium in future if this is possible...

I don't know if nucleis with so low mass-number is instable due to neutron fission. And it also depends of you want to use thermal neutrons or higher energy neutrons, or maybe even have protons as probes.

Anyway, i know research is going on to have a Thorium isotope instead of Uranium, there is much more thorium in the world + it don't give long lived daugther nucleids which are radioactive. Also transmutation of "burned out" uranium is under research. There is a lot of info if you google. And Astronuc is a guru about these things.

But I am very sure that we will get fusion working before uranium runs out. But still, we need to take care of the Uranium-waste. My opinion.
 
  • #22
Thank you for all replies..
 

1. What is nuclear fission?

Nuclear fission is a process in which the nucleus of an atom splits into two or more smaller nuclei, releasing a large amount of energy. This process is commonly used in nuclear power plants to generate electricity.

2. What role do heavy nuclei play in nuclear fission?

Heavy nuclei, such as uranium and plutonium, are used in nuclear fission reactions because they are unstable and can easily split into smaller nuclei, releasing a large amount of energy.

3. Are there lighter options for nuclear fission?

Yes, there are lighter options for nuclear fission. In addition to heavy nuclei, scientists are also exploring the use of lighter elements, such as thorium, as potential fuel sources for nuclear fission reactions.

4. What are the advantages of using nuclear fission as an energy source?

Nuclear fission has several advantages as an energy source, including its high energy density, low carbon emissions, and ability to generate large amounts of electricity from a relatively small amount of fuel.

5. What are the potential risks associated with nuclear fission?

The main potential risks associated with nuclear fission include the release of radioactive materials, the possibility of accidents or meltdowns, and the challenge of properly managing and disposing of nuclear waste. These risks can be mitigated through strict safety regulations and proper waste management protocols.

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