One last Radioactivity Question

[darren t]

One last Radioactivity Question!

Im not sure how to do this calculation

Cells containing 0.8 curies of 32P were to be disposed of as waste when their total radioactivity had decreased to less that uCi. Calculate the period for which these should be stored

Now 32P has a half life of 14.2 days?

Im sorry to bother you guys but I have a test on monday and this could be a question. Thanks in advance!

How does this answer look??

A = B*(1/2)^(t/14.2)

at t = 0, B = 0.8 curie,

A = 0.8*(1/2)^(t/14.2)

when A = 1 uCi

0.000001 = 0.8*(1/2)^(t/14.2)

0.000001/0.8 = (1/2)^(t/14.2)

t/14.2*log(1/2) = log(0.000001/0.8)

t = 14.2*log(0.000001/0.8)/log(1/2)

t = 278.46 days

 

[Jhero]

Therefore, the cells should be stored for approximately 278.46 days before their total radioactivity decreases to less than 1 uCi. This calculation takes into consideration the half-life of 32P, which is 14.2 days. It is important to properly dispose of radioactive waste to ensure the safety of both humans and the environment. Good luck on your test!