Is Poincare wrong about no preferred geometry?

In summary: I am not sure about the exact conditions for this to hold. I have variously heard that spacetime should be coverable by harmonic coordinates, or that its topology is R3 X R. I know the former is sufficient, but I am not sure it is necessary. I am not sure whether the latter is true. Anyway, the basic idea is that a curved spacetime where the metric is the degree of freedom, can also be physically equivalent to a field (the metric perturbation, not necessary small or linear) on a flat spacetime.When you say harmonic coordinates do you mean coordinate functions \alpha ^{(i)} that satisfy \triangledown ^{a}\triangled
  • #1
jmarshall
5
0
I heard that some physicists are trying to determine the spacial/geometric curvature of the universe by measuring the angles of distant stars (a very large triangle).

Is this possible? Or is Poincare correct when he said that there is no preferred geometry and that there is no experiment that will show one(Euclidean vs. non-Euclidean) the truest?
 
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  • #3
Thank you for your response. Sadly the geometry of space section does not cover the mathematical problem of there being no preferred geometry.

I believe that a curved space geometry has been solved that has all the logical consistencies that Euclidean geometry has. If this is true then can't this geometry be used in place of the standard Euclidean geometry? And if this is true then can't we make the argument that we live in a curved space just as easily as a flat (Euclidean) one?
 
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  • #4
jmarshall said:
Thank you for your response. Sadly the geometry of space section does not cover the mathematical problem of there being no preferred geometry.

I believe that a curved space geometry has been solved that has all the logical consistencies that Euclidean geometry has. If this is true then can't this geometry be used in place of the standard Euclidean geometry? And if this is true then can't we make the argument that we live in a curved space just as easily as a flat (Euclidean) one?

in Physics today there is no fixed geometry of space but rather a time evolving geometry that is determined by the distribution of matter.

In mathematics there are many geometries and Euclidean geometry has not preferred.

Historically it was beleived that Euclidean geometry was the natural geometry of space that in fact it was an intrinsic feature of the idea of space itself. In the 18'th century another plane geometry was discovered so Euclidea geometry was seen not to be intrinsic and scientists treid to make measurements to determine which of the two was true in space. today it is realized that neither of these two describe the actual geometry of space.
 
  • #5
jmarshall said:
Thank you for your response. Sadly the geometry of space section does not cover the mathematical problem of there being no preferred geometry.

I believe that a curved space geometry has been solved that has all the logical consistencies that Euclidean geometry has. If this is true then can't this geometry be used in place of the standard Euclidean geometry? And if this is true then can't we make the argument that we live in a curved space just as easily as a flat (Euclidean) one?

Under some circumstances a flat spacetime and a curved spacetime are physically equivalent. However the flat spacetime geometry is not Euclidean, but Minkowskian. This is discussed in Chapter 11 of http://books.google.com/books?id=Gz...+bend+rulers+kip+thorne&source=gbs_navlinks_s .
 
  • #6
atyy said:
Under some circumstances a flat spacetime and a curved spacetime are physically equivalent.
What circumstances are you thinking of? This doesn't sound correct in general, so I assume you are thinking of some exceptional circumstances.
 
  • #7
Hi,

Is the geometry really Minkowskian? Or is applying a Minkowskian geometry the most simple mathematical model to describe the relation between light, masses, and moving bodies in those special cases?

This is the core of my original question. Is there really a fundamental geometry?
 
  • #8
DaleSpam said:
What circumstances are you thinking of? This doesn't sound correct in general, so I assume you are thinking of some exceptional circumstances.

I am not sure about the exact conditions for this to hold. I have variously heard that spacetime should be coverable by harmonic coordinates, or that its topology is R3 X R. I know the former is sufficient, but I am not sure it is necessary. I am not sure whether the latter is true. Anyway, the basic idea is that a curved spacetime where the metric is the degree of freedom, can also be physically equivalent to a field (the metric perturbation, not necessary small or linear) on a flat spacetime.
 
  • #9
When you say harmonic coordinates do you mean coordinate functions [itex]\alpha ^{(i)}[/itex] that satisfy [itex]\triangledown ^{a}\triangledown _{a}\alpha ^{(i)} = 0[/itex]? If so, I know that given a 2 dimensional manifold [itex]M[/itex] with a lorentzian metric and a harmonic function [itex]\alpha :M\rightarrow \mathbb{R}[/itex] together with the harmonic function [itex]\beta :M\rightarrow \mathbb{R}[/itex] conjugate to [itex]\alpha[/itex], [itex]\forall p\in M[/itex] there exists a neighborhood [itex]U[/itex] of [itex]p[/itex] on which we can transform the lorentzian metric to harmonic coordinates but I'm not sure what this has to do with flatness. This is actually a problem in Wald (chapter 3 problem 7) and assuming I didn't make calculation errors (which I very well may have!) I certainly didn't get an identically vanishing Riemann curvature tensor. Hopefully I didn't misunderstand what you were saying atyy. Cheers.
 
  • #10
WannabeNewton said:
When you say harmonic coordinates do you mean coordinate functions [itex]\alpha ^{(i)}[/itex] that satisfy [itex]\triangledown ^{a}\triangledown _{a}\alpha ^{(i)} = 0[/itex]? If so, I know that given a 2 dimensional manifold [itex]M[/itex] with a lorentzian metric and a harmonic function [itex]\alpha :M\rightarrow \mathbb{R}[/itex] together with the harmonic function [itex]\beta :M\rightarrow \mathbb{R}[/itex] conjugate to [itex]\alpha[/itex], [itex]\forall p\in M[/itex] there exists a neighborhood [itex]U[/itex] of [itex]p[/itex] on which we can transform the lorentzian metric to harmonic coordinates but I'm not sure what this has to do with flatness. This is actually a problem in Wald (chapter 3 problem 7) and considering I didn't make calculation errors I certainly didn't get an identically vanishing Riemann curvature tensor. Hopefully I didn't misunderstand what you were saying atyy!

The basic idea is that instead of considering the basic degree of freedom to be the metric g, we consider the basic degree of freedom h, where g=h+η.

I understand poorly the exact conditions for this equivalence to hold, so let me give a reference: http://arxiv.org/abs/gr-qc/0411023 .

A similar idea is in http://relativity.livingreviews.org/Articles/lrr-2006-3/fulltext.html [Broken], Eq 62.
 
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  • #11
Oh are you talking about the usual procedure of having a background flat space - time and having a perturbation field propagate on the background flat space - time?
 
  • #12
WannabeNewton said:
Oh are you talking about the usual procedure of having a background flat space - time and having a perturbation field propagate on the background flat space - time?

Yes, but with the perturbation not necessarily small or linear.
 
  • #13
atyy said:
Yes, but with the perturbation not necessarily small or linear.
Ah ok. The second link looks rather extensive and interesting, thanks for that! Till next time.
 
  • #14
WannabeNewton said:
Ah ok. The second link looks rather extensive and interesting, thanks for that! Till next time.

The first link is also a classic. I hope to understand it properly some day:)
 
  • #15
atyy said:
The first link is also a classic. I hope to understand it properly some day:)
I was reading until spin and Yang - Mills came up and I said yeah...this is where it ends for me :frown: sigh
 
  • #16
jmarshall said:
I heard that some physicists are trying to determine the spacial/geometric curvature of the universe by measuring the angles of distant stars (a very large triangle).

Is this possible? Or is Poincare correct when he said that there is no preferred geometry and that there is no experiment that will show one(Euclidean vs. non-Euclidean) the truest?

My understanding of the contemporary meaning of "no perferred geometry" is that it means that the distribution of matter determines the geometry, not that the geometry can't ever be measured.

So I don't see any issue with measuring the geometry of the universe, I don't think this contradicts there being "no preferred geometry".

It's possible that Poincare's meaning is different than the contemporary one, I suppose. But it would be odd to say that we couldn't measure a geometry, unless one insists that distances are arbitrary. There might be a philosophy that claims this, I suppose, but it gets into metaphysics rather than physics.

For the most part, physics insists that the Lorentz interval is well defined, the Lorentz interval plus a notion of simultaneity (which is mostly regarded as conventional) defies distance, and that the geometry of space-time is the geometry of the Lorentz interval. Thus the geometry of space-like slices (the usual notion of distance) can be deterined from the geometry of space-time plus the details of the method used to slice it into space + time, i.e from the geometry of space-time plus some notion of simultaneity.
 
  • #17
jmarshall said:
I heard that some physicists are trying to determine the spacial/geometric curvature of the universe by measuring the angles of distant stars (a very large triangle).

Is this possible? Or is Poincare correct when he said that there is no preferred geometry and that there is no experiment that will show one(Euclidean vs. non-Euclidean) the truest?

If I'm not mistaken post #1 is referring only to the spatial geometry of the universe ("spacial,measure of angles...") not to the spacetime geometry as it seems to be interpreted by many here but it is confusing since in a later post he refers to Minkowskian spacetime.

I'll address here the easier spatial case only:the spatial geometry according to mainstream cosmology is indeed not exactly determined but it is highly constrained to three models, following the FRW model the three only possible spatial geometries are the Euclidean, the hyperbolic and the elliptic geometry with respectively 0, negative and positive constant curvature.
Empirically the curvature cannot ever be exactly measured because there is a limit of precision in detection and an inherent error that means we could be missing very small curvatures, so far the observations indicate a near flat geometry but with very wide error bars that don't allow us to discard either positive or negative small curvatures.

I would like to see that comment of Poincare in context, can you give a reference?
 
  • #18
I think people are getting confused in this discussion. Poincare's philosophical views did not agree with the standard modern interpretation of GR. From wikipedia:

Poincaré believed that Newton's first law was not empirical but is a conventional framework assumption for mechanics. He also believed that the geometry of physical space is conventional. He considered examples in which either the geometry of the physical fields or gradients of temperature can be changed, either describing a space as non-Euclidean measured by rigid rulers, or as a Euclidean space where the rulers are expanded or shrunk by a variable heat distribution. However, Poincaré thought that we were so accustomed to Euclidean geometry that we would prefer to change the physical laws to save Euclidean geometry rather than shift to a non-Euclidean physical geometry.

This is what Poincare meant by no preferred geometry.
 
  • #19
I would like to see that comment of Poincare in context, can you give a reference?
Also when did he say it? He died in 1912, had he lived to see GR he might have had a different view.
 
  • #20
pervect said:
My understanding of the contemporary meaning of "no perferred geometry" is that it means that the distribution of matter determines the geometry, not that the geometry can't ever be measured.

So I don't see any issue with measuring the geometry of the universe, I don't think this contradicts there being "no preferred geometry".

It's possible that Poincare's meaning is different than the contemporary one, I suppose. But it would be odd to say that we couldn't measure a geometry, unless one insists that distances are arbitrary. There might be a philosophy that claims this, I suppose, but it gets into metaphysics rather than physics.

Yes, "no preferred geometry" usually refers to a different concept nowadays, that matter determines geometry.

Poincare's point about measuring the geometry of the universe was that to do so you have to assume your ruler is straight. But his point was that instead of straight ruler and bent geometry, one could also imagine bent rulers and straight geometry. I believe the ability to have flat and curved spacetime versions of Newton, Nordstrom, and Einstein gravity illustrate the spirit of his point.

Naty1's quote from Thorne is relevant: "Isn't it conceiveable that spacetime is actually flat but the clocks and rulers we use to measure it are actually rubbery?...yes...Both viewpoints give precisely the same predictions for any measurements performed...Some problems are solved most easily and quickly using the curved spacetime paradigm; others, using the flat spacetime...Black hole problems, for example, are most amenable to curved spacetime techniques; gravitational wave problems (for, example computing the waves produced when two neutron stars orbit each other) are most amenable to flat spacetime techniques...the laws that underlie the two paradigms are mathematically equivalent...That is why physicsts were not content with Einstein's curved spacetime paradigm and have developed the flat spacetime paradigm as a supplement to it..."
 
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  • #21
If a flat and hyperbolic geometry can be constructed to describe the same physical event and it is only convention or convenience as to which to select, then can we use the angles made by distant stars to show that we inhabit a flat (euclidean) geometry? Is it impossible to discover the shape of our spatial geometry?

And is it more useful to just consider the interactions of massive bodies by the most convenient mathematical model and not interpret the model used as a representation of the nature(shape) of space?
 
  • #22
Here is a quote that covers the general idea.

Poincare Science and Hypothesis“The straight line is a line such that a figure of which this line is a part can move without the mutual distances of its points varying, and in such a way that all the points in this straight line remain fixed" ? Now, this is a property which in either Euclidean or non-
Euclidean space belongs to the straight line, and belongs to it alone. But how can we
ascertain by experiment if it belongs to any particular concrete object ? Distances
must be measured, and how shall we know that any concrete magnitude which I have
measured with my material instrument really represents the abstract distance? We
have only removed the difficulty a little farther. In reality, the property that I have just
enunciated is not a property of the straight line
(75) alone; it is a property of the straight line and of distance. For it to serve as an
absolute criterion, we must be able to show, not only that it does not also belong to
any other line than the straight line and to distance, but also that it does not belong to
any other line than the straight line, and to any other magnitude than distance. Now,
that is not true, and if we are not convinced by these considerations, I challenge any
one to give me a concrete experiment which can be interpreted in the Euclidean
system, and which cannot be interpreted in the system of Lobatschewsky. As I am
well aware that this challenge will never be accepted, I may conclude that no
experiment will ever be in contradiction with Euclid's postulate; but, on the other
hand, no experiment will ever be in contradiction with Lobatschewsky's postulate.
5. But it is not sufficient that the Euclidean (or non-Euclidean) geometry can ever be
directly contradicted by experiment. Nor could it happen that it can only agree with
experiment by a violation of the principle of sufficient reason, and of that of the
relativity of space. “
 

1. What is Poincare's theory of no preferred geometry?

Poincare's theory of no preferred geometry, also known as the principle of relativity, states that the laws of physics should be the same for all observers in uniform motion, regardless of their relative velocity or position.

2. Is Poincare's theory still accepted in modern science?

Yes, Poincare's theory of no preferred geometry is still accepted in modern science, particularly in the field of physics. It is a fundamental principle in the theory of relativity and has been extensively tested and confirmed through experiments and observations.

3. What is the significance of Poincare's theory in the field of cosmology?

Poincare's theory of no preferred geometry is significant in cosmology as it allows for a consistent understanding of the universe and its structure. It removes the need for a fixed reference frame, which was a major challenge in early theories of the universe.

4. Are there any criticisms of Poincare's theory of no preferred geometry?

One of the main criticisms of Poincare's theory is that it does not account for non-inertial reference frames, such as accelerating frames. This led to the development of the general theory of relativity, which expands on Poincare's theory to include non-inertial frames.

5. How does Poincare's theory of no preferred geometry relate to Einstein's theory of relativity?

Einstein's theory of relativity builds upon Poincare's theory of no preferred geometry, expanding it to include non-inertial frames and incorporating the concept of gravity. Poincare's theory is often considered a precursor to Einstein's theory and is still an important principle in modern physics.

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