Decaying E-Field: Spatially Uniform in Conductors

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In summary, the conversation discusses the concept of a "spatially uniform E-field" in a conductor and the equation E=Eo*exp(-t/tau) is used to demonstrate this. The equation requires the use of curl(H) = ErEo*dE/dt + sigma*E and the assumption that curl H is equal to zero. The speaker is having trouble finding a geometrical argument for why curl(H) = zero and is seeking hints. The conversation also touches on the meaning of "spatially uniform" and how it relates to the equations for B and H. Ultimately, it is agreed that while spatially uniform solutions exist, they are not physically realistic.
  • #1
sachi
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We are asked to show that we can have a "spatially uniform E-field" in a conductor according to E=Eo*exp(-t/tau) where tau=ErEo/sigma

where Er is the relative permittivity and sigma is the conductivity. I know we need to use curl(H) = ErEo*dE/dt + sigma*E
and for some reason we say that curl H is equal to zero. then we get a simple ODE to solve. I'm having trouble coming up with a geometrical argument for why curl(H) = zero. any hints appreciated.
 
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  • #2
If the electric field is spatially uniform, what does the [tex] \nabla \times E = - \frac{\partial B}{\partial t} [/tex] equation imply about [tex] B [/tex] and [tex] H [/tex]?
 
  • #3
I'm not too sure about the meaning of "spatially uniform". If we just assume that E=E(t) and let it be in say the x direction then we can show that curl(E) has no x components, and the rest of the problem works out. But surely a wave has to have some spatial dependence e.g E = E(z,t)?
 
  • #4
Nope, spatially uniform means independent of position. Indeed, as you show here, spatially uniform solutions do exist though of course they are ultimately unphysical.
 

1. What is a decaying E-field?

A decaying E-field refers to an electric field that is decreasing in strength over time. This can occur in conductors, where the electric field is initially present due to the movement of charge, but eventually dissipates as the charges come to a steady state.

2. How is the E-field distributed in conductors?

In conductors, the E-field is distributed uniformly throughout the material. This means that the strength of the electric field is the same at all points within the conductor.

3. What is the cause of the decaying E-field in conductors?

The decaying E-field in conductors is caused by the redistribution of charges within the material. When an external electric field is applied, charges within the conductor will move until they reach a state of equilibrium, resulting in a decrease in the electric field strength.

4. How does the decay of the E-field relate to the conductivity of a material?

The decay of the E-field is directly related to the conductivity of a material. Conductors with higher conductivity will have a faster rate of decay of the E-field due to the ease of charge movement within the material.

5. Can a decaying E-field be completely eliminated in conductors?

No, a decaying E-field cannot be completely eliminated in conductors. As long as an external electric field is applied, there will always be some level of electric field present in the material. However, this field may become negligible over time as the charges reach a steady state.

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