- #1
dwdeclare
- 2
- 0
i'm having difficulty trying to figure out a problem i thought of.
a projectile is launched upwards at a 45 degree angle 100 m above a surface. below is a target whose horizontal distance is 5 m from the launch point. just as the projectile is launched, the target moves horizontally at a constant 9 m/s.
what would the velocity of the launch have to be in order to hit the target below?
so far i have come up with:
5 + 9t = vcos45t
for t = time i have:
(see attachment)
but I'm having difficulty knowing how to incorporate it properly into the equations.
i've reduced the time to:
√([.02548v2 + 100]/4.9) + (.07215v)
is there an easier way to go about solving this?
any help would be greatly appreciated.
thank you
a projectile is launched upwards at a 45 degree angle 100 m above a surface. below is a target whose horizontal distance is 5 m from the launch point. just as the projectile is launched, the target moves horizontally at a constant 9 m/s.
what would the velocity of the launch have to be in order to hit the target below?
so far i have come up with:
5 + 9t = vcos45t
for t = time i have:
(see attachment)
but I'm having difficulty knowing how to incorporate it properly into the equations.
i've reduced the time to:
√([.02548v2 + 100]/4.9) + (.07215v)
is there an easier way to go about solving this?
any help would be greatly appreciated.
thank you