Confused on how they derived this

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In summary, the conversation discusses the quantized energy levels of an electron in a one-dimensional atom, with a focus on the equation E_n = n^2(h^2/(8ml^2)). The conversation also explains the inclusion of c^2 in the equation and its relation to the conversion factor hc = (1239.8eV*nm).
  • #1
Pengwuino
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The book I am using did a simple little algebra and it is showing the quantized energy levels of an electron in a one-dimensional atom of width 0.1nm.

They did this:

[tex]
\begin{array}{l}
E_n = n^2 \frac{{h^2 }}{{8ml^2 }} \\
E_n = n^2 \frac{{h^2 c^2 }}{{8mc^2 l^2 }} \\
E_n = n^2 \frac{{(1239.8eV*nm)^2 }}{{(8)(0.511*10^6 eV)(0.1nm)^2 }} \\
\end{array}[/tex]

But where did the c^2 go on top?
 
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  • #2
The [tex] c [/tex] has been put with the [tex] h [/tex] to give something with units of [tex] [E][T]\frac{[L]}{[T]} = [E][L] [/tex], and numerically [tex] h c = 1239.8[/tex] eV nm. This is one of those common estimation factors, although I remember it as [tex] \hbar c \sim 200 [/tex] eV nm.
 
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  • #3
Oh ok i get why they did this. They have a conversion at the front of the book for hc = (1239.8eV*nm) that i didn't notice or make the connection to.
 

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