- #1
ur5pointos2sl
- 96
- 0
The problem states:
A horizontal force of 77 N pushes a 12 kg block up a frictionless incline that makes an angle of 60 degrees with the horizontal.
What is the normal force that the incline exerts on the block?
After drawing the FBD I can see there are only 2 forces acting in the Y direction which are Fn and W.
so Fn = mg cos theta = 12 kg ( 9.81 m/s^2) * cos (60 deg) = 58.86 N.
This is a homework problem and when attempting to submit the problem on webassign it keeps telling me it is incorrect. I am not sure where I am going wrong or if there is an error with the problem.
Thanks.
A horizontal force of 77 N pushes a 12 kg block up a frictionless incline that makes an angle of 60 degrees with the horizontal.
What is the normal force that the incline exerts on the block?
After drawing the FBD I can see there are only 2 forces acting in the Y direction which are Fn and W.
so Fn = mg cos theta = 12 kg ( 9.81 m/s^2) * cos (60 deg) = 58.86 N.
This is a homework problem and when attempting to submit the problem on webassign it keeps telling me it is incorrect. I am not sure where I am going wrong or if there is an error with the problem.
Thanks.