- #1
Satvik Pandey
- 591
- 12
Homework Statement
A wedge of mass m and angle θ is placed on a smooth ground. As shown in the diagram A is a point on ground. A particle also having mass m is dropped from a height h at a horizontal distance x from A . It finally touches the ground at point B . Find √3AB in metres.
Details and Assumptions
Take m=5kg ,h=2√2 metre ,x=1metre.tanθ=1/√2
The collision of the ball with the wedge is elastic and the wedge is free to move.
THIS IS THE FIGURE https://d3pq38zxuosm5i.cloudfront.net/solvable/2676130fa9.e594e044b6.ZQmdPV.jpg
Homework Equations
AS the collision is elastic so momentum of system is conserved and kinetic energy is conserved.
The Attempt at a Solution
given tanθ=1/sq.root(2)
using this we can find the the initial distance of ball above point A(v3)=3/√2.
so velocity of ball when it collided wedge=√(3√2)g.
since K.E. is conserved so 3√2g=v1^2+v2^2...(1)(V1 is velocity of ball after collision and v2 is velocity of wedge after collision)
now tanθ=1/sq.root(2) so θ=35.26
applying law of conservation of momentum in Y-direction
3/√2g=-v1 sin2θ+0......(2)(considering upward direction -ve).
Are my two equations correct.
Answer of this question is 1.268.