- #1
chhitiz
- 221
- 0
can somebody please tell me if there is any way to find all values of k for which 6k2+4k is of form 6ab+5a+b? eg. for k=1, 6k2+4k=10=6x0x2+5x2+0
Finding Values of k for 6k2+4k in the Form 6ab+5a+b?
In summary, the conversation discusses finding values for k that will make the expression 6k2+4k equal to the form 6ab+5a+b. It is suggested that any rational number for k will work, and an example using k=1 is given. However, it is clarified that a cannot be 0, but can be any positive integer, while b can be greater than or equal to 0.
- #2
Almutairi
- 6
- 0
I might have misunderstood the question, but Based on what you made a=2 and b=0. Can you give them any value you want?
In that case can't you always make a=0, b= (6K 2 +4k)?
So that 6k2+4k is always of the form 6ab+5a+b, where K is any rational number.
eg. for k=1, 6k2+4k=10=6x0x10+5x0+10
Or should I just go back to my lunch
In that case can't you always make a=0, b= (6K 2 +4k)?
So that 6k2+4k is always of the form 6ab+5a+b, where K is any rational number.
eg. for k=1, 6k2+4k=10=6x0x10+5x0+10
Or should I just go back to my lunch
- #3
chhitiz
- 221
- 0
yeah sorry about that, but a can't be 0. has to be a integer>0. b,though can be >=0
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