jahaddow said:Homework Statement
Ok, I have a cubic function, y=(x-6)(x-1)(x-9) or y = x3-16x2+69x-54
I then have four tangents to make a quadrilateral, the tangents are as follows.
y=7.75x+14.75
y=-6.25x+56.25
y=7.75x + -76.231
y=-6.25x + 31.602
I need to find the area inside the tangents, except I have no idea where to start, Thankyou for any help in advance.
jahaddow said:A Parallelogram, But I don't see how I can get the area from the equations?
jahaddow said:So, How do I do that?
The formula for finding the area inside four tangents is A = 2r2, where r is the radius of the circle.
To determine the radius of the circle, you can use the formula r = √(a2 + b2 + c2 + d2) / 4, where a, b, c, and d are the lengths of the four tangents.
No, the area inside four tangents cannot be negative. This is because area is a measure of the space occupied by a shape, and it cannot have a negative value.
The area inside four tangents is used in geometry to find the area of a circle when given four tangents. It is also used in various geometric constructions and proofs.
Yes, there is a relationship between the area inside four tangents and the circumference of the circle. The circumference of a circle is equal to 2πr, which is also equal to the perimeter of the shape formed by the four tangents. This shape has the area of 2r2, which is the same as the area inside four tangents.