- #1
Sucks@Physics
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Initially, a 2.00kg mass is whirling at the end of a string in a circular path of .750 m on a horizontal frictionless surface with a tangential speed of 5 m/s. The string has been slowly winding around a vertical rod, and a few seconds later the length of the string has shortened to .250 m. What is the instantaneous speed of the mass at the moment the string reaches a length of .250m.
I = mr^2 but i must be missing a formula because that won't work because it would give me a smaller number and it obviously speeds up the shorter the string gets.
I = mr^2 but i must be missing a formula because that won't work because it would give me a smaller number and it obviously speeds up the shorter the string gets.