3d surface in 4d space

by dEdt
Tags: space, surface
 Math Emeritus Sci Advisor Thanks PF Gold P: 39,564 In general, we can specify a n-1 dimensional hyperplane in a space of n dimensions with a "normal vector" and a point in the hyperplane. In four dimensions, every point can be written as $(x_1, x_2, x_3, x_4)$ and a four dimensional vector of the form $a\vec{ix}+ b\vec{j}+ c\vec{k}+ d\vec{l}$. If the origin, (0, 0, 0, 0) is in the hyperplane, then we can write $x_1\vec{ix}+ x_2\vec{j}+ x_3\vec{k}+ x_4\vec{l}$ and so the dot product is $$ax_1+ bx_2+ cx_3+ dx_4= 0$$ giving an equation for that hyper plane. But, again, that assumes the hyperplane contains the point (0, 0, 0). Another plane, perpendicular to the same vector, but not containing (0, 0, 0), cannot be written that way.