A couple of projectile trajectory-related questions

[FlyinDutchman]

First one (to check with others on whether or not it's correct, although I'm sure it's very easy)

Homework Statement

A vector makes an angle, theta, with the horizontal. The horizontal and vertical components of the vector will be equal in magnitude if angle theta is
Four Choices
(1) 30 degrees
(2) 45 degrees
(3) 60 degrees
(4) 90 degrees

Homework Equations

None I believe

The Attempt at a Solution

1. I drew out a right triangle
2. Angle theta is located at the left portion of the right triangle
3. Right angle = 90 degrees, of course
4. Two congruent angles will have congruent sides; as a result, 45 degrees is my answer (also because the two angles have to be equal and must add up to 90).

I'll add another one in a bit after I get this out of the way.

 

[PhanthomJay]

correct. If you have additional questions, you might want to start a new post.

 

[thomate1]

Your solution is correct! When a vector is at a 45 degree angle with the horizontal, the horizontal and vertical components will be equal in magnitude. This is because the triangle formed by the vector and its components is a right isosceles triangle. Good job on using your knowledge of congruent angles and sides to solve the problem. Keep up the good work!