- #1
Gogarty
- 1
- 0
This Is really simple I just can't remember what way Sin and Cosine go
Here is the problem:
7 (b) A uniform ladder rests on rough
horizontal ground and leans against
a smooth vertical wall.
The length of the ladder is 5 m and
its weight is 80 N.
The angle between the ladder and the
ground is 60
The ladder is on the point of slipping.
(i) Show on a diagram all the forces acting on the ladder.
(ii) Calculate the value of the coefficient of friction
right so I realize the weight acts through the center of gravity in this case half way up. but it also acts towards the wall. is it the sin or cos of the angle that acts down. which goes horizontaly? I know how to do the rest just what way do the components of the weight break up? Is it 80 cos(60 or 80 Sin(60 to find the force acting to the right ?
Homework Statement
Here is the problem:
7 (b) A uniform ladder rests on rough
horizontal ground and leans against
a smooth vertical wall.
The length of the ladder is 5 m and
its weight is 80 N.
The angle between the ladder and the
ground is 60
The ladder is on the point of slipping.
(i) Show on a diagram all the forces acting on the ladder.
(ii) Calculate the value of the coefficient of friction
right so I realize the weight acts through the center of gravity in this case half way up. but it also acts towards the wall. is it the sin or cos of the angle that acts down. which goes horizontaly? I know how to do the rest just what way do the components of the weight break up? Is it 80 cos(60 or 80 Sin(60 to find the force acting to the right ?