Help calculating torque of servo for gripper to hold part.

In summary, the conversation discusses a problem involving calculating the minimal servo torque needed for a gripper to hold a part in place. The given information includes the mass of the load, the friction between the load and gripper walls, and the diameter of the wheel on which the pegs that pull the grippers are located. The equations used in attempting to solve the problem include force to squeeze times friction between load and gripper walls being greater than the mass of the cube, torque being equal to force times radius, and the summation of vertical forces on the gripped object being equal to zero. The conversation also includes corrections on the formulas used and further attempts at finding the correct solution.
  • #1
duzO
5
0

Homework Statement


I have this problem. I'm trying to calculate the minimal servo torque for the gripper to hold the part in place.
http://img52.imageshack.us/img52/8784/96199865.jpg

Mass of load is 170grams. u friction between load and walls is 0.5.
the diameter of wheel on which the pegs that pull the grippers is 2cm.

Homework Equations


Force to squeeze * Friction between load and gripper walls > Mass of cube
Torque=Force * radius

The Attempt at a Solution


F(friction)=0.17kg x 0.5=0.085N
F(G)=0.17kg x G = 1.666N
F=F(f) + F(g)= 1.751N

T=1.751N*0.01m=0.01751Nm

This is probably wrong...

Any ideas?
 
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  • #2
duzO said:
F(f) = (0.17 kg)*0.5 = 0.085 N

duzO: This is not the correct formula for friction force. What is the general formula for friction force? Keep trying. Your formula for weight, F(g), is correct. Don't you want the summation of vertical forces on the gripped object to equal zero? Keep developing your formulas. You are getting close.
 
  • #3
nvn said:
duzO: This is not the correct formula for friction force. What is the general formula for friction force? Keep trying. Your formula for weight, F(g), is correct. Don't you want the summation of vertical forces on the gripped object to equal zero? Keep developing your formulas. You are getting close.

https://www.physicsforums.com/mgc_gloss/latex_images/mgc_gloss_extexpl_39-4.png ?

so itll be F=umg . friction force=friction x normal force

so you are saying that mg=umg+F ?
1.66=0.833+F;
F=0.827N ?
 
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  • #4
W acts downward. 2*Fs acts upward. Perform a summation of vertical forces, and set it equal to zero.
duzO said:
|Fs| ≤ mus*N

Very good. Now what is N? Write an expression for N. N comes from the servo, right? Try again.
 
  • #5
nvn said:
W acts downward. 2*Fs acts upward. Perform a summation of vertical forces, and set it equal to zero.


Very good. Now what is N? Write an expression for N. N comes from the servo, right? Try again.

mg + 2(umN) = 0 ?

N=Torque/radius?

so Torque=gR/2u = 0.098Nm?
 
  • #6
m*g should be negative, not positive. Fs = mu*N, not u*m*N. N = T/diameter, not T/radius. m = mass, mu = static coefficient of friction, N = normal force, Fs = frictional force. Try again.
 

What is torque and why is it important for a servo gripper to hold a part?

Torque is a measure of rotational force, and it is important for a servo gripper to hold a part because it determines how much rotational force the gripper can exert on the part. A higher torque means that the gripper can hold onto the part more securely.

How do I calculate the torque needed for my servo gripper to hold a specific part?

To calculate the torque needed for a servo gripper to hold a specific part, you will need to know the weight of the part, the distance from the gripper to the center of mass of the part, and the coefficient of friction between the gripper and the part. You can then use the formula torque = force x distance to calculate the required torque.

What factors can affect the torque needed for a servo gripper to hold a part?

The weight and shape of the part, the coefficient of friction between the gripper and the part, and the distance between the gripper and the center of mass of the part are all factors that can affect the torque needed for a servo gripper to hold a part. Additionally, external forces such as wind or vibrations can also impact the required torque.

How can I increase the torque of my servo gripper to hold a part?

There are a few ways to increase the torque of a servo gripper. You can use a gripper with a higher torque rating, adjust the position of the gripper closer to the center of mass of the part, or increase the coefficient of friction between the gripper and the part by using different materials or adding grip-enhancing features.

Is there a maximum torque that a servo gripper can exert on a part?

Yes, there is a maximum torque that a servo gripper can exert on a part. This maximum torque is dependent on the size and specifications of the servo motor used in the gripper. It is important to check the torque rating of the servo motor and make sure it is suitable for the intended application.

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