Water Balloon Trebuchet/catapolt Physics Problems

In summary, the designer attempted to solve the problem by calculating the velocity needed to launch a water balloon using formulas from basic physics and trigonometry. However, they were unable to find a consistent solution and asked for help.
  • #1
Ransom7D
2
0
Hello,

This is my first post and I hope it's not incorrectly placed...

Recently I made the naive decission to design a water balloon trebuchet as a pet project. Furthermore, I wanted to calculate the exact specifications of the design ( counterweight, arm lengths, ect.) using only the knowledge that the desired distance was to be 50m, the release point was to be at 45 degrees, and that the avg. water balloon would weigh around 1kg.

Determining the necessary velocity at the point of release was reletivly easy. I used the formulas, x=t(v)cos() and y=t(v)sin()-(.5)(g)t^2 , pluged in the release angle of 45 and the distance of 50m, then solved the horizontal formula for t and substituted it into the vertical formula when y is 0. this resulted in a velocity of 11.07m/s. I was excited, but little did i know what was to come.

So next i drew a simple desing and determined that I needed to find the mass of the weight, and the two arm lengths. furthermore I determined that the total force of the counterweight minus the total force of gravity on the projectile arm would have to equal a force whose velocity was 11.o7m/s. So I sought the neccsary formulas, and from there I realized my folly. At first i began with a simple F=ma style approch, but remembered that this was a curcular trajectory problem. I then began using F=mv^2/r for a bit until i remembered that was for centripital force and would be of no use.

I have tried a miriad of other approches ranging from determining angular velocity and acceleration to formulas in inertia, to even turning the whole thing sideways and attempting to turn it into a modified trajectrory problem with gravity as wind resistance and centripital force as gravity! I have yet to get any consistant results. So now I've decided to give in and ask for help.

Can someone please point me in the proper direction on how to figure this out?

(note: I'm a rising senior in high school with only a knowledge of precal and basic physics guiding me... i fear I am over my head but am obsessed!)
 
Last edited:
Physics news on Phys.org
  • #2
Ransom7D said:
Recently I made the naive decission to design a water balloon trebuchet as a pet project.

Well, I suggest you first try a simplified version of the problem. Lessons learned will help you follow the discussion by Franco on his http://www.real-world-physics-problems.com/trebuchet-physics.html" page.

A true trebuchet has the rigid swingarm, and then there is the sling with the pouch. As a simplification you can:
- Leave out the sling
- Attach the counterweight directly to the short end.

For the simplified case let's say the swingarm hits a cross member, just like the swingarm of an Onager hits a cross member, releasing the payload. Let's say that initially the swingarm is at a 45 degrees angle, with the long end pointing down, and that at the instant of launch the the swingarm is pointing up at a 45 degrees angle.

Then you can divide the setup in four contributing elements:
- The counterweight
- The payload
- The long end of the swingarm (holding the payload)
- The short end of the swingarm (holding the counterweight)

Each of the contributing elements has its own moment of inertia with respect to the pivot point. For each of the elements gravity contributes a torque. You have to evaluate the resultant torque that is acting relative to the pivot point. Once you have the resultant torque and the combined moment of inertia you can compute the angular acceleration of the payload. That should enable you to home in on an angular acceleration that leads up to the needed launch velocity.

You may have to simplify even more. The torque from gravity depends on the angle of the swingarm. When the swingarm is level the torque is largest, when the swing arm is at an angle the torque is correspondingly smaller. You can opt to take a guessed average for that torque, and then you treat the torque as constant throughout.

If you manage such a simplified setup then maybe you'll be equipped to handle a less simplified version. Good luck.
 
Last edited by a moderator:
  • #3
Will you put your trebuchet on wheels or will it be fixed in position?
 

1. What is a water balloon trebuchet/catapolt?

A water balloon trebuchet/catapolt is a type of siege weapon that uses a counterweight to launch water balloons at a target. It is based on the same principles as a traditional trebuchet/catapolt, but instead of launching projectiles, it launches water balloons.

2. How does a water balloon trebuchet/catapolt work?

A water balloon trebuchet/catapolt works by using a counterweight to create a force that launches the water balloon. The counterweight is placed on one end of an arm, while the water balloon is placed on the other end. When the arm is released, the counterweight falls, causing the arm to swing and launch the water balloon towards the target.

3. What factors affect the distance a water balloon trebuchet/catapolt can launch?

The distance a water balloon trebuchet/catapolt can launch depends on various factors, including the weight and size of the counterweight, the length and strength of the arm, the angle at which the arm is released, and the air resistance. The distance can also be affected by external factors such as wind and the weight and shape of the water balloon.

4. How can I calculate the optimal design for a water balloon trebuchet/catapolt?

To calculate the optimal design for a water balloon trebuchet/catapolt, you will need to use principles of physics, such as projectile motion and torque. You will also need to consider the different factors that affect the distance and accuracy of the launch, such as the weight and length of the arm, the counterweight, and the angle of release. There are also online calculators and simulations that can help you determine the optimal design for your specific needs.

5. Are there any safety precautions I should take when using a water balloon trebuchet/catapolt?

Yes, it is essential to take safety precautions when using a water balloon trebuchet/catapolt. Make sure to use appropriate materials and follow instructions carefully. Always wear protective gear, such as goggles, when launching water balloons. Also, make sure to have a clear and open area for the launch to avoid any potential hazards or injuries.

Similar threads

Replies
1
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
10
Views
2K
Replies
2
Views
177
  • Mechanics
Replies
6
Views
5K
Replies
4
Views
7K
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Sci-Fi Writing and World Building
Replies
3
Views
401
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
11
Views
765
  • Introductory Physics Homework Help
Replies
2
Views
1K
Back
Top