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brunie
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Can't really figure out where to start. Any help would be appreciated.
A 575 kg satellite is in a circular orbit at an altitude of 550 km above the Earth's surface. Because of air friction, the satellite eventually falls to the Earth's surface, where it hits the ground with a speed of 2.10 km/s. How much energy was transformed to internal energy by means of friction?
E = -1/2 G Ms Me / r
v = 2 pi r / T
E = - G Me Ms / Re + d
M = mass
R = radius
ok so 575kg, 550000 m above Earth's surface, falls at 2100 m/s
5.97 x 10^24 kg is Earth's mass (Me)
6378100 for Earth radius (Re)
Ms is mass of satelite
G is constant
so for Ek = 1/2mv^2
= 0.5*575*2100^2
= 1267875 kJ
E = - G Me Ms / Re + d
= (6.67 x 10^-11)(5.97 x 10^24)(575) / (6378100 + 550000)
= -3.305 x 10^10
so do I substract E in orbit by Ek at crash (E - Ek)??
Homework Statement
A 575 kg satellite is in a circular orbit at an altitude of 550 km above the Earth's surface. Because of air friction, the satellite eventually falls to the Earth's surface, where it hits the ground with a speed of 2.10 km/s. How much energy was transformed to internal energy by means of friction?
Homework Equations
E = -1/2 G Ms Me / r
v = 2 pi r / T
E = - G Me Ms / Re + d
M = mass
R = radius
The Attempt at a Solution
ok so 575kg, 550000 m above Earth's surface, falls at 2100 m/s
5.97 x 10^24 kg is Earth's mass (Me)
6378100 for Earth radius (Re)
Ms is mass of satelite
G is constant
so for Ek = 1/2mv^2
= 0.5*575*2100^2
= 1267875 kJ
E = - G Me Ms / Re + d
= (6.67 x 10^-11)(5.97 x 10^24)(575) / (6378100 + 550000)
= -3.305 x 10^10
so do I substract E in orbit by Ek at crash (E - Ek)??
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