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TMFKAN64
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Golden Rule for Decays in Griffiths' "Introduction to Elementary Particles"?
Hello, I'm getting a bit bogged down in constant factors while reading Griffiths' "Introduction to Elementary Particles", 1st edition. In particular, I'm having problems with equation 6.15:
[tex]
d\Gamma = |M|^{2}\frac{S}{2\hbar m_{1}}\left[
\left(\frac{c\, d^{3}p_{2}}{(2\pi)^{3}2E_{2}}\right)
\left(\frac{c\, d^{3}p_{3}}{(2\pi)^{3}2E_{3}}\right)\cdots
\left(\frac{c\, d^{3}p_{n}}{(2\pi)^{3}2E_{n}}\right)\right]\times
(2\pi)^{4}\delta^{4}(p_{1}-p_{2}-p_{3}\cdots-p_{n})
[/tex]
I've found some slides online at http://www-pnp.physics.ox.ac.uk/~libby/Teaching/Lecture4.pdf that discuss normalizing the wave function and phase space so it is Lorentz invariant, but this only explains part of my problem. What I still don't understand is:
Any assistance would be greatly appreciated.
Hello, I'm getting a bit bogged down in constant factors while reading Griffiths' "Introduction to Elementary Particles", 1st edition. In particular, I'm having problems with equation 6.15:
[tex]
d\Gamma = |M|^{2}\frac{S}{2\hbar m_{1}}\left[
\left(\frac{c\, d^{3}p_{2}}{(2\pi)^{3}2E_{2}}\right)
\left(\frac{c\, d^{3}p_{3}}{(2\pi)^{3}2E_{3}}\right)\cdots
\left(\frac{c\, d^{3}p_{n}}{(2\pi)^{3}2E_{n}}\right)\right]\times
(2\pi)^{4}\delta^{4}(p_{1}-p_{2}-p_{3}\cdots-p_{n})
[/tex]
I've found some slides online at http://www-pnp.physics.ox.ac.uk/~libby/Teaching/Lecture4.pdf that discuss normalizing the wave function and phase space so it is Lorentz invariant, but this only explains part of my problem. What I still don't understand is:
- Where do the [tex]c[/tex] in the numerators of the momentum terms come from?
- Where does the [tex](2\pi)^{4}[/tex] term before the delta function come from?
- Where did the [tex]\hbar^{3n}[/tex] in the density of states go? (The [tex]\frac{1}{(2\pi\hbar)^{3n}}[/tex] is responsible for the [tex]2\pi[/tex] factors in the momentum terms, right?)
- Why doesn't the first fraction have [tex]m_{1}c^{2}[/tex] in the denominator?
Any assistance would be greatly appreciated.