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warrior2014
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Net force and Newton's laws of motion!
A barge is hauled along a straight-line section of canal by two horses harnessed to tow ropes and walking along the tow paths on either side of the canal. Each horse pulls with a force of 490 N at an angle of 19° with the centerline of the canal. What is the net force on the barge?
Fx= F1x + F2x...
Fy= F1y + F2y...
Fnet
I broke it into components and got the following:
F1x= 490cos19
F2x=490cos19
F1y=490sin19
F2y=490sin19
I'm not too sure where to go from here. I think you add all the Fx components and Fy components, then square them and take the square root but when I tried that, I got it wrong, which was 980 N (and they do not give you the correct answer).
Any help will be appreciated!
Homework Statement
A barge is hauled along a straight-line section of canal by two horses harnessed to tow ropes and walking along the tow paths on either side of the canal. Each horse pulls with a force of 490 N at an angle of 19° with the centerline of the canal. What is the net force on the barge?
Homework Equations
Fx= F1x + F2x...
Fy= F1y + F2y...
Fnet
The Attempt at a Solution
I broke it into components and got the following:
F1x= 490cos19
F2x=490cos19
F1y=490sin19
F2y=490sin19
I'm not too sure where to go from here. I think you add all the Fx components and Fy components, then square them and take the square root but when I tried that, I got it wrong, which was 980 N (and they do not give you the correct answer).
Any help will be appreciated!