Chemistry - calculating equilibrium constant, what am I doing wrong?

In summary, at equilibrium, .0055 mol of N2O4 remains in a 1.00-L flask charged with .400 mol of N2O4. The equilibrium constant for this reaction is 13.
  • #1
confusedbyphysics
62
0
I feel like I know what I'm doing but I'm not getting an answer that is offered. Heres the question:

Dinitrogentetraoxide partially decomposes according to the following equilibrium:

N2O4 (g) ---> 2NO2 (g) (an arrow going other way too)


A 1.00-L flask is charged with .400 mol of N2O4. At equilibrium at 373 K, 0.0055 mol of N2O4 remains. Equil. constant for this reaction is __________.

a. 2.2 x 10^-4
b. 13
c. 0.22
d. 0.022
e. 0.87K = [NO2]^2 / [N204]

N2O4 goes from .4 to .0055 mol, so that is a change of .3945 mol, which must be the equilibrium amount of the 2NO2. Since the volume is just 1 L

K = [.3945 M]^2 / [.0055 M] = 28.3

but this is not one of the choices.

what am I doing wrong?
 
Last edited:
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  • #2
First thing you're "doing wrong" is attempting to reproduce the errors in the instructional software; you already came up with an answer of one hundred something, didn't you. You wouldn't be stating, "... .3945 mol, which must be the equilibrium amount of the 2NO2," otherwise.

If you know what you're doing, it's your call how you handle it; try to reproduce the software errors (and not rock the boat), or present your work to the instructor (or go to the department head) and get a few TAs into trouble.
 
  • #3
confusedbyphysics said:
I feel like I know what I'm doing but I'm not getting an answer that is offered. Heres the question:

Dinitrogentetraoxide partially decomposes according to the following equilibrium:

N2O4 (g) ---> 2NO2 (g) (an arrow going other way too)


A 1.00-L flask is charged with .400 mol of N2O4. At equilibrium at 373 K, 0.0055 mol of N2O4 remains. Equil. constant for this reaction is __________.

a. 2.2 x 10^-4
b. 13
c. 0.22
d. 0.022
e. 0.87K = [NO2]^2 / [N204]

N2O4 goes from .4 to .0055 mol, so that is a change of .3945 mol, which must be the equilibrium amount of the 2NO2.
No, there is no law of conservation of moles !

If you use up 1 mol of N2O4, you make 2 moles of NO2. In any case, the correct answer still does not exist in the provided list. Have you copied the question correctly ? Or have you mistyped choice (b) ?
 
  • #4
Hi, yes the answers are exactly as my WEBCT has them.

I understand where I was messing up on the moles, but now I have an answer of 113!

Relate the change
.3945 mol N2O4/L (2 mol NO2/1 mol N2O4) = .789 mol NO2/L

0+.789 = .789 for the NO2 so [.789]^2/[.0055] = 113

is that the answer that should be correct? the 13 was just typed in incorrectly and should have been put in as 113 into webct??
 
  • #5
confusedbyphysics said:
is that the answer that should be correct? the 13 was just typed in incorrectly and should have been put in as 113 into webct??
Yes, that would be my guess. Take this to your TA or instructor.
 
  • #6
Equilibrium constant Help!

How do we calculate equilibrium constant if we do not know what the concentration is and all else is given in the formula?
 
  • #7
Please elaborate (and don't hijack the threads).
 

1. Why do I need to calculate the equilibrium constant?

Calculating the equilibrium constant is important in understanding the thermodynamics of a chemical reaction. It helps determine the direction and extent of a reaction, as well as the concentrations of reactants and products at equilibrium.

2. How do I calculate the equilibrium constant?

The equilibrium constant, denoted by Keq, is calculated by taking the ratio of the concentrations of products to reactants, each raised to their respective stoichiometric coefficients. It is important to use the equilibrium concentrations, not initial concentrations, in the calculation.

3. What units are used for the equilibrium constant?

The equilibrium constant is unitless, as it is a ratio of concentrations. However, the values of Keq can vary greatly depending on the units used for concentrations. It is important to use consistent units when calculating and comparing equilibrium constants.

4. Why do my calculated equilibrium constants not match literature values?

There are several reasons why calculated equilibrium constants may not match literature values. Some common reasons include experimental errors, incomplete reactions, and assumptions made in the calculation. It is important to carefully follow the steps and assumptions used in the calculation to ensure accuracy.

5. How do I know if my calculated equilibrium constant is reasonable?

The magnitude of the equilibrium constant can give an indication of the relative amounts of reactants and products at equilibrium. A large Keq (>10) indicates that the reaction favors the products, while a small Keq (<10) indicates that the reaction favors the reactants. However, the actual value of Keq can vary greatly depending on the specific reaction and conditions, so it is important to compare it to literature values and consider other factors such as temperature and pressure.

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