Electromagnetic induction with two coils and an iron heart

[kakadas]

Homework Statement

Two coils are place on an iron heart, like in the picture. The top Coil is connected to a galvanometer, the second could be connected to a power source.

Homework Equations

Will an electric current flow through the top coil when:

a) connecting and then disconnecting the DC chain that the bottom coil is connected to.

b) connecting the bottom coil to a DC source.

c) connecting the bottom coil to a AC source.

d) removing the top coil upwards from an iron heart, when the bottom coil is connected to a DC source.

e) removing the iron heart upwards, when the bottom coil is connected to a DC source.


In all cases briefly explain Your answers.

The Attempt at a Solution

 

[jbsteele]

a) No, an electric current will not flow through the top coil when connecting and then disconnecting the DC chain that the bottom coil is connected to. This is because the top coil is not part of the circuit and therefore cannot be affected by any changes in the bottom coil's circuit. b) Yes, an electric current will flow through the top coil when connecting the bottom coil to a DC source. This is because the top coil is now part of the circuit, and a current can flow through it when the bottom coil is connected to a DC source. c) Yes, an electric current will flow through the top coil when connecting the bottom coil to an AC source. This is because an alternating current is produced when an AC source is used, which will cause the current in the top coil to switch directions periodically. d) No, an electric current will not flow through the top coil when removing the top coil upwards from an iron heart, when the bottom coil is connected to a DC source. This is because the top coil is no longer part of the circuit and therefore cannot be affected by any changes in the bottom coil's circuit. e) No, an electric current will not flow through the top coil when removing the iron heart upwards, when the bottom coil is connected to a DC source. This is because the iron heart is not part of the circuit and therefore cannot be affected by any changes in the bottom coil's circuit.