- #1
ph123
- 41
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A solid sphere rolls without slipping down a ramp that is at an angle of 32 above horizontal. The magnitude of the acceleration of the center of mass of the sphere as it rolls down the ramp is?
sum of torques = I(alpha)
rmgsin32 = (2/5)mr^2(a_tan/r)
the radii drop out as one would expect with no radius given. the masses also drop out since they weren't provided.
gsin32 = (2/5)a_tan
(9.8 m/s^2)sin32 = (2/5)a_tan
a = 12.98 m/s^2
This result clearly makes no sense because it is greater than the accelertion due to gravity. But that was the only approach I could think to use since I was only given the angle of the incline. Any ideas?
sum of torques = I(alpha)
rmgsin32 = (2/5)mr^2(a_tan/r)
the radii drop out as one would expect with no radius given. the masses also drop out since they weren't provided.
gsin32 = (2/5)a_tan
(9.8 m/s^2)sin32 = (2/5)a_tan
a = 12.98 m/s^2
This result clearly makes no sense because it is greater than the accelertion due to gravity. But that was the only approach I could think to use since I was only given the angle of the incline. Any ideas?